We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].
AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13
BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13
CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13
DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13
The two polygons are squares with the same side lengths.
But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions:
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.
The third condition was not proven.
X^2+9x+9x+81
x^2+18x+81
for factoring it
Answer:
yes,
Step-by-step explanation:
For example, if it lands on 4, then u do 1*2*2*2*2 because it is 4, if 5, then do 1 *2*2*2*2*2, the two will change according to the hours.
Answer:
The correct option is 1.
Step-by-step explanation:
It is given that the Brian, Kelsey, and Geoff each have a remote-controlled car. They simultaneously started their cars and drove them in a straight line away from a motion sensor.
It means they are travelling at a constant rate.
Slope formula:

From the given table it is clear that the of Brian's car from the sensor is 34 at 1 sec and 38 at 3 sec. The rate of change is

It means the Brian's car traveled at the rate of 2 cm per sec.
From the given table it is clear that the of Brian's car from the sensor is 27 at 1 sec and 31 at 3 sec. The rate of change is

It means the Kelsey's car traveled at the rate of 2 cm per sec.
From the given table it is clear that the of Brian's car from the sensor is 27 at 1 sec and 33 at 3 sec. The rate of change is

It means the Geoff's car traveled at the rate of 3 cm per sec.
Since Brian's and Geoff's car traveled at the same rate, therefore option 1 is correct.