Solve the equation by replacing x with -7 and then -1.
Then subtract the two to find the difference and divide that by the difference between -7 and -1.
f(-7) = -7^2 + 2(-7) -8 = 49 -14 -8 = 27
f(-1) = -1^2 + 2(-1) -8 = 1 -2 - 8 = -9
Difference between 27 and -9 = -36
Difference between -1 and -7 = -6
Rate of change = -36 /-6 = 6
Answer is 8671/6 which is the third choice
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Work Shown:
Find the first term of the sequence by plugging in n = 1
a_n = (5/6)*n + 1/3
a_1 = (5/6)*1 + 1/3 replace n with 1
a_1 = 5/6 + 1/3
a_1 = 5/6 + 2/6
a_1 = 7/6
Repeat for n = 58 to get the 58th term
a_n = (5/6)*n + 1/3
a_58 = (5/6)*58 + 1/3 replace n with 58
a_58 = (5/6)*(58/1) + 1/3
a_58 = (5*58)/(6*1) + 1/3
a_58 = 290/6 + 1/3
a_58 = 145/3 + 1/3
a_58 = 146/3
Now we can use the s_n formula below with n = 58
s_n = (n/2)*(a_1 + a_n)
s_58 = (58/2)*(a_1 + a_58) replace n with 58
s_58 = (58/2)*(7/6 + a_58) replace a_1 with 7/6
s_58 = (58/2)*(7/6 + 146/3) replace a_58 with 146/3
s_58 = (58/2)*(7/6 + 292/6)
s_58 = (58/2)*(299/6)
s_58 = (58*299)/(2*6)
s_58 = 17342/12
s_58 = 8671/6
Similarities: They both are polynomials of degree 2, both of their graphs is a parabola, both have either 2 or 0 real solutions, they are both continuous functions over R
(DOS= difference of two squares, PST=perfect square trinomial
Differences: PST has three terms, whereas the difference of squares has 2. PST's factors are both the same, whereas DOS's elements are conjugates of each other. DOS can always be factored into two distinct polynomials with rational coefficients, whereas PST has two same polynomial factors.
Hi,
Answer:
k = 
Step-by-step explanation:
Subtract 4k from both sides
6k - 4k = 2k
2k - 8 = 15
Add 8 on both sides (you want to get rid of the 8 in order to leave the k alone)
2k = 23
k = 23/2
Have a good day!
Answer:
a) h'(t)= (6cos3t,-9sin3t,3![\sqrt[]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B5%7D)
cos3t)
b) t=0.93994736+πn/3
c) Magnitude of h(t) is 3 which is a constant, so h(t) lies on a sphere
Step-by-step explanation:
