Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
530.087 trust me
Step-by-step explanation:
It is false or 8/9 is equal to 1
Answer:
Correct answer: sin 2Θ = - 24/25
Step-by-step explanation:
If under the standard position you think that the first arm (side) belongs to the positive direction of the x axis and the second one passes through a given point then it is:
if we form a right triangle with sides 3 and 4 then the hypotenuse is 5.
sin Θ = 4/5 and cos Θ = - 3/5
we know that the formula for double the value of the angle is:
sin 2Θ = 2 sinΘ cosΘ = 2 · 4/5 · ( - 3/5) = - 24/25
sin 2Θ = - 24/25
God is with you!!!
Answer:
-8
Step-by-step explanation:
Hope this helps!