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frez [133]
4 years ago
13

Why must the value of the sine ratio for an acute angle

Mathematics
1 answer:
Fynjy0 [20]4 years ago
4 0

Answer:

Because of the range of the sine function.

Step-by-step explanation:

The reason why the value of the sine ratio for an acute angle

of a right triangle must always be a positive value less

than 1 has to do with the the range of the sine function.

The range of the sine function is

- 1 \leqslant y \leqslant 1

But in the first quadrant all y-values are positive and acute angles are less than 90°.

Therefore the range will now be 0≤y<1 for acute angles.

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A sequence is defined recursively by
Andrei [34K]

9514 1404 393

Answer:

  an = 4×34^(n-1)

Step-by-step explanation:

If your recursive definition is ...

  \begin{cases}a_1=4\\a_{n}=34a_{n-1}\end{cases}

this defines a geometric sequence with a first term a1 = 4 and a common ratio of r = 34. The general form of the explicit function is ...

  a_n=a_1\times r^{n-1}

For the values shown here, the explicit definition of the sequence is ...

  \boxed{a_n=4\times 34^{n-1}}

8 0
2 years ago
Liza buys 4 yards of fabric for $8.48. How much was the fabric per yard?
levacccp [35]

Answer:

the fabric per yard was 2.12

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
3,5,12,55,648,?<br> What follows the sequence? Thank you
Sladkaya [172]

Answer:35,585

Step-by-step explanation:

3x5 -3 = 12

5x12 -5 = 55

12x55 -12 = 648

55x648 -12 = 35,585

5 0
2 years ago
Karen is estimating how much flour she needs if each cake requires 2 2/6 cups of flour and she is making 3 cakes. Explain how ma
gregori [183]

Answer:

The answer is 7 cups

Step-by-step explanation:

1 cake-2 2/6 cups

Which can also be written as

1 cake-14/6 cups

3 cakes-x cup

Cross multiply

x=14/2

x=7

Therefore Karen needs 7 cups of flour to make 3 cakes

6 0
3 years ago
Marla did 65 sit ups each day for one week use the distributive property to show an expression you can use to find the total num
Elis [28]
7(65)=total sit-ups
You get 455
5 0
3 years ago
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