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alukav5142 [94]
2 years ago
11

What is the median of 9, 6, 5, 3, 64, 7, 4, 2

Mathematics
1 answer:
Alexxx [7]2 years ago
5 0

Answer:

it's 5.5

Step-by-step explanation:

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Which set of graphs can be used to find the solution set to 3e* > >-x?
kobusy [5.1K]

The attached graph represents the solution set of 3e^x > \frac 12^x

<h3>How to determine the graph?</h3>

The complete options are not given.

So, I would plot the graph that represents the solution set

The inequality is given as:

3e^x > \frac 12^x

Start by splitting the inequalities as follows:

f(x) > 3e^x

g(x) > \frac 12^x

The above means that we plot the graphs of f(x) and g(x) to represent the solution set

See attachment

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7 0
2 years ago
1. The chairman of the community bazaar is assigning people to chair committees. How many different
pickupchik [31]

Answer:

720

Step-by-step explanation:

8 0
2 years ago
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If 1 pound = 16 ounces, what is the weight of the bananas ( 2.5 lbs ) in ounces.
Galina-37 [17]

Answer:

Hi there

Your answer is

40 ounces

Step-by-step explanation:

1lb = 16oz

2.5lbs = xoz

1lb = 16oz

*2.5

2.5lbs = 40oz

7 0
2 years ago
Read 2 more answers
A linear function has a slope of Negative StartFraction 7 Over 9 EndFraction and a y-intercept of 3. How does this function comp
dem82 [27]

It has the same slope and the same y-intercept, that is, <u>option a</u> is the right choice.

A linear function in the slope-intercept is written as y = mx + b, where m represents the slope of the line and b represents the y-intercept.

We are given two linear functions and are asked to compare them.

<u>First </u><u>linear function:</u>

Slope (m) = -7/9.

y-intercept (b) = 3.

Therefore, the linear function is: y = (-7/9)x + 3.

<u>Second </u><u>linear function</u>:

Function given: y + 11 = (-7/9)(x - 18)

or, y + 11 = (-7/9)x + (-7/9)(-18)

or, y = (-7/9)x + 14 - 11 = (-7/9)x + 3.

Therefore, slope (m) = (-7/9)

y-intercept (b) = 3.

Therefore, we can say that it has the same slope and the same y-intercept, that is, <u>option a</u> is the right choice.

Learn more about linear functions at

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7 0
1 year ago
Sin2A+Sin2B÷Sin2A-Sin2B=Tan(A+B)÷Tan(A-B) Prove that​
igor_vitrenko [27]

Take L.H.S sin2A+sin2B/sin2A-sin2B

= sin2A+sin2B/sin2A-sin2B

Put

[sinC+sinD = 2sin(C+D)/2cos(C-D)/2]

[sinC-sinD = 2cos(C+D)/2.sin(C-D)/2]

= 2 sin(2A+2B)/2 cos(2A-2B)/2 / 2 cos(2A+2B) sin(2A-2B)

= sin(A+B).cos(A-B)/cos(A+B).sin(A-B)

= sin(A+B)/cos(A+B) . cos(A-B)/sin(A-B)

= tan(A+B).cot(A-B)

= tan(A+B).1/tan(A-B)

= tan(A+B)/tan(A-B)

∴ Hence we proved sin2A+sin2B/sin2A-sin2B=tan(A+B)/tan(A-B)

8 0
2 years ago
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