5.00+0.67+0.07 that's it I believe
y < - 8 or y > 4
inequalities of the form | x | > a always have solutions of the form
x < - a or x > a
we have to solve
y + 2 < - 6 or y + 2 > 6
y + 2 < - 6 ( subtract 2 from both sides )
y < - 8
or
y + 2 > 6 ( subtract 2 from both sides )
y > 4
these can be combined using interval notation
y ∈ (- ∞, - 8 ) ∪ (4, ∞ )
As a check
substitute chosen values of x from each interval
y = - 10 : | - 10 + 2 | = | - 8 | = 8 > 6 this is true
y = 12 : | 12 + 2 | = | 14 | = 14 > 6 which is also true
Three consecutive odd integers are n, n+2 and n+4
n + n+2 + n+4 = -87
3n + 6 = -87
3n = -87 - 6
3n = -93
n = -93/3
n = -31
n+2 = -31 + 2 = -29
n+4 = -31 + 4 = -27
The numbers are -31, -29 and -27
Answer:
b
Step-by-step explanation:
4/3*pi*r^3
Answer:
1. 12
2. 0.04
3. 196
Step-by-step explanation:
1. 12*12= 144
2. 1/25= 0.04
3. (11-8)^2= 3^2= 9
