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ludmilkaskok [199]
3 years ago
10

What is the value of f?

Mathematics
1 answer:
emmasim [6.3K]3 years ago
6 0

Answer:

42

Step-by-step explanation:

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Nothng to it just mark them

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The value of <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D" id="TexFormula1" title="\sqrt[3]{x}" alt="\sqrt[3]{x}" ali
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15pts! (Multiple choice answer)Please answer with work
MariettaO [177]

To find the area of a rectangle, we multiply the Base by the Height.                        In this case the:   Base = AB   and     Height = BC  

So to get the area, we multiply AB by BC.                                               (and we know that <em>BC = 5x+5/x+3</em> <em>and BC = [3x+9/2x-4)</em>  

So we would do:

\frac{5x+5}{x+3} x \frac{3x+9}{2x-4}                              

Note: When multiplying fractions together, we multiply the numerator by the numerator, and the denominator by the denominator.                                        

For example \frac{2}{8} x \frac{3}{4} = \frac{6}{32}    


Answer: \frac{5x+5}{x+3} x \frac{3x+9}{2x-4} = \frac{(5x+5)(3x+9)}{(x+3)(2x-4)}

\frac{(5x+5)(3x+9)}{(x+3)(2x-4)} = \frac{5(x+1)*3(x+3)}{(x+3)*2(x-2)} [<em>Note: </em><em>we are able to factorise some brackets to make the sum easier. For example we can factor out the 5 in (5x+5) to get: 5(x+1)   ]</em>

Now lets simplify by multiplying the 5 and 3 together in the numerator:

\frac{5(x+1)*3(x+3)}{(x+3)*2(x-2)} = \frac{15 (x+1)(x+3)}{(x+3)*2(x-2)}

If you notice, there is a (x+3) in numerator and the denominator. This means that we can cancel out the (x+3), to get the most simplified expression for the area:

\frac{15 (x+1)(x+3)}{(x+3)*2(x-2)} = \frac{15(x+1)}{2(x-2)}

Final Simplified Answer: \frac{15(x+1)}{2(x-2)} which is the last option

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kenny6666 [7]

50%

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