Question

H(-4)=x^2-8x please solve

Answer 1

Answer:

Putting h=-4 in the function $h(x)=x^2-8x$ we get $\mathbf{h(-4)=48}$

Step-by-step explanation:

We are given: $h(x)=x^2-8x$

We need to find h(-4)

Put x= -4 and solve:

$h(x)=x^2-8x\\Put \ x=-4\\h(-4)=(-4)^2-8(-4)\\h(-4)=16+32\\h(-4)=48$

So, putting h=-4 in the function $h(x)=x^2-8x$ we get $\mathbf{h(-4)=48}$