H(-4)=x^2-8x please solve

Mathematics

1 answer:

Ivan3 years ago

8 0

Answer:

Putting h=-4 in the function $h(x)=x^2-8x$ we get $\mathbf{h(-4)=48}$

Step-by-step explanation:

We are given: $h(x)=x^2-8x$

We need to find h(-4)

Put x= -4 and solve:

$h(x)=x^2-8x\\Put \ x=-4\\h(-4)=(-4)^2-8(-4)\\h(-4)=16+32\\h(-4)=48$

So, putting h=-4 in the function $h(x)=x^2-8x$ we get $\mathbf{h(-4)=48}$

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