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myrzilka [38]
3 years ago
9

Which is the graph of f(x) = (2) ^-x

Mathematics
1 answer:
Len [333]3 years ago
3 0

this ia the graph, give me brainliest answer

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The ordered pairs in the table below represent a linear function.
GenaCL600 [577]

Answer:

\displaystyle m=2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Slope Formula: \displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (6, 2)

Point (9, 8)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>

  1. Substitute in points [Slope Formula]:                                                            \displaystyle m=\frac{8-2}{9-6}
  2. [Fraction] Subtract:                                                                                         \displaystyle m=\frac{6}{3}
  3. [Fraction] Divide:                                                                                            \displaystyle m=2
5 0
3 years ago
Use the explicit formula an = a1 + (n - 1) • d to find the 350th term of the sequence below. 57, 66, 75, 84, 93, ... A. 3234 B.
mylen [45]
To use the equation we need a1 and d(the common difference).
We have a1 = 57, we need to find d.
93-84 = 9; 84-75=9; 75-66=9; 66-57=9
d = 9
a350 = 57 + (350-1)(9)
a350 = 57 + (349)(9)
a350 = 57 + 3141
a350 = 3198
4 0
3 years ago
Read 2 more answers
Find the cost of painting a cubical block of side length 3.2 cm, if painting costs $5 per cm2.
SashulF [63]
<h3><u>Answer</u>:- </h3>

\longrightarrow \sf \$ \: 307.2

<h3><u>Solution:-</u></h3>

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

\green{ \underline { \boxed{ \sf{Surface \: area  \:of  \:Cube = 6a^2}}}}

  • <u>where a is side of the cube </u>

\begin{gathered}\\\quad \sf Surface \: area  \:of  \:Cube = 6\times(3.2)^2  \\\end{gathered}

\begin{gathered}\\\implies \quad \sf  6\times 3.2\times3.2   \\\end{gathered}

\begin{gathered}\\\implies \quad \sf  61.44 cm^2  \\\end{gathered}

Now,

\maltese \sf Cost  \:of  \:painting \: 1 \: cm² = \$ 5

\sf Cost \: of \: painting \: 61.44  \:cm²=61.44×5

\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2

\leadstoThus it would cost $ 307.2 to paint the entire cubical block.

3 0
2 years ago
Which of the following would eliminate the variable on the left side of the given equation? 36 - 19w = -6w + 41.  1. add -19w  2
Paladinen [302]
W=5/13 you just eliminate the negative sign
5 0
3 years ago
A rectangle has a length five more than twice the width. If the perimeter is 22 units find the width and length
PtichkaEL [24]

Set the following: Length = L    Width = W

The length is twice the width:    L = 2*W     or:  W = L/2

Perimeter: P = 60ft = 2*L + 2*W

Substituting L for W in the perimeter equation gives:

P = 60ft = 2*L + 2*(L/2) = 2*L + L = 3L

L = 60ft/3 = 20ft    W=L/2=20ft/2=10ft

Verify result:  Perimeter= P = 60ft = 2L + 2W = 2*20ft +2*10ft = 40ft+20ft = 60ft

The area of the rectangular is: Area = A = Length*Width = L*W = 20ft*10ft = 200 (ft)^2

-Rosie

3 0
3 years ago
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