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MatroZZZ [7]
3 years ago
8

80 + ? + -30 = 0 whats in the middle

Mathematics
1 answer:
Dmitry [639]3 years ago
6 0

Answer: The answer is -50

because 80 + -50 = 30 and 30 + -30= 0              .

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10 small and 8 large cost $192. 20 small and 1 large cost $99. What is cost of a small
seraphim [82]

Answer:

Step-by-step explanation:

small=s,    s=3.99

large=l,       l=19.20

10s+8l=192.20

20s+l=99

we can see that in the second equation, 20s+l=99

l=99-20s

lets replace l in the first equation

10s+8(99-20s)=192.20

10s+792-160s=192.20

-150s=-792+192.20

150s=599.80

s=3.99

l=99-20(3.99)=99-79.80=19.20

7 0
3 years ago
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Plz help me well mark brainliest if correct!!
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1 hour

Step-by-step explanation:

Each graph shown lasts for 1/2 hour / 30 minutes

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4 years ago
Miss Johnson bought a pair of jeans on sale for $30. The original price was $50. By what percent did the price of the jeans chan
svetlana [45]

Answer:

the price changed by 40%

6 0
3 years ago
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The first train leaves the station at 6:15 a m. The second train leaves at 6:55 am. How much does the sec ond train leave the st
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second train leaves 40 minutes after

7 0
3 years ago
The owner of a restaurant is reviewing customer complaints. In a random sample of 227 complaints, 57 complaints were about the s
iragen [17]

Answer:

0.1375 to 0.3624

Step-by-step explanation:

Given :The owner of a restaurant is reviewing customer complaints. In a random sample of 227 complaints, 57 complaints were about the slow speed of the service.

To Find :Create a 95% confidence interval for the proportion of complaints that were about the slow speed of the service.

Solution:

n = 227

x = 57

Formula of confidence for proportion: \widecap{p}-z_{\frac{\alpha}{2}}\sqrt{\frac{\widecap{p}\widecap{q}}{n}} to  \widecap{p}+z_{\frac{\alpha}{2}}\sqrt{\frac{\widecap{p}\widecap{q}}{n}}

\widecap{p}=\frac{x}{n}

\widecap{p}=\frac{57}{227}

\widecap{p}=0.25

\widecap{q}=1-\widecap{p}

\widecap{q}=1-0.25

\widecap{q}=0.75

z at 95% is 1.96

Substitute the values in the formula :

Confidence for proportion: 0.25-1.96\sqrt{\frac{0.25 \times 0.75}{57}} to 0.25+1.96\sqrt{\frac{0.25 \times 0.75}{57}}

Confidence for proportion: 0.1375 to 0.3624

Hence 95% confidence interval for the proportion of complaints that were about the slow speed of the service is  0.1375 to 0.3624

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3 years ago
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