Answer:
The answer to your questions is below
Step-by-step explanation:
4.-
In a 45°-45°-90° triangle, the length of the legs are "x" and the length of the hypotenuse is x![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
Then, in this problem, the length of the leg is 7 then the length of the hypotenuse will be 7![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
5.- In a 30°-60°-90° triangle, the length of the hypotenuse is 2x, the length of the longer leg is x
and the length of the shorter leg is x.
In this problem we have the length of the hypotenuse = 20 and find x.
2x = 20
x = 20/2
x = 10
longer leg = x![x\sqrt{3} = 10\sqrt{3}](https://tex.z-dn.net/?f=x%5Csqrt%7B3%7D%20%3D%3Cstrong%3E%2010%5Csqrt%7B3%7D)
6.- nonzero
7.- hypotenuse = 20 cm
Find x
2x = 20
x = 20/2
x = 10
Shoter leg = x = 10 cm