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Ivanshal [37]
3 years ago
9

What is the GCF of 18 and 22

Mathematics
2 answers:
Simora [160]3 years ago
6 0
The GCF Of 18 and 22 is 2
12345 [234]3 years ago
5 0
The GCf is 2. It is 2 because no larger number can go into 18 and 22
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Math can you guys help me PLS
MissTica

Answer:

The surface area of the triangular prism is 84 square centimeters.

Step-by-step explanation:

The surface area of a figure is exactly what it means, the area of its outer surface or the added areas of each face that makes the figure.

Nets are a way to find surface area easier because it is an outline of the faces of the 3d figure.

But since we don’t have a net, we will just find the area of each face that forms this right triangular prism:

The two congruent triangular bases:

1/2 x 4 x 3 = 6 cm^2

6 x 2 = 12 cm^2

Lateral bottom rectangular face:

6 x 3 = 18 cm^2

Lateral to the right rectangular face:

5 x 6 = 30 cm^2

Lateral to the left rectangular face:

4 x 6 = 24 cm^2

Add up all the values:

12 + 18 + 30 + 24 = 84

The SA is 84 square centimeters

4 0
3 years ago
A circular disc has a circumference of 16pi meters. if we multiply the radius of the circular disc is by 10, what is the circumf
Flauer [41]

The circumference of the new disc 160Π that is 10 time of old circumference.

Step-by-step explanation:

Given,

Circumference of circular disc = 16Π (pi = Π)

Let, the radius of the circle be 'r'

Formula

The circumference of a circle with r radius = 2 Π r

According to the problem,

2 Π r = 16Π

or, 2r = 16 ( by eliminating the value of Π from both the side)

or, r = 8

Now, we multiply the radius by 10

so, the new radius is 8 X 10 = 80

Now the circumference = 2 Π X 80

= 160Π

Hence, the new circumference also will be 10 times of the older one.

6 0
4 years ago
I need help with this question? Please and thank you!!!!<br> #15
4vir4ik [10]
Ref3vygrnvrgnubub  frrrrrrrrvcrf
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3 years ago
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muminat

Answer:

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Y =2.5X +4

Step-by-step explanation:

3 0
3 years ago
*<br> ate: Find 8% of 40.<br> nt)
olasank [31]
The answer is 3.2.
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3 years ago
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