That would be 177.5 in standard form.
The answer is 220 because you would just have to round 1 to 2 than everytging behind it is a zero
Answer:
The answer is below
Step-by-step explanation:
Given that:
The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.
The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

a) For x < 2:

From normal distribution table, P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%
b) For x = 2:

For x = 11:

From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337
c) For x = 11:

From normal distribution table, P(x < 11) = P(z < 1.67) = 0.9525
d) For x = 2:

For x = 5:

From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) = 0.2033- 0.0188 = 0.1845
e) For x = 5:

From normal distribution table, P(x < 5) = P(z < -0.83) = 0.2033
Answer:
The probability a person selected random is not suffering from Malaria is 0.725.
Step-by-step explanation:
Denote the events as follows:
X = a person is suffering from Malaria
M = a man
W = a woman
The information provided is:
P (M) = P (W) = 0.50
P (X|M) = 0.10
P (X|W) = 0.45
Compute the probability a person selected random is suffering from Malaria as follows:


Then the probability a person selected random is not suffering from Malaria is:
P (X') = 1 - P (X)
= 1 - 0.275
= 0.725
Answer:
4/5 is greater
Step-by-step explanation: