Answer:
We draw line AB which is perpendicular to the 14 cm side
Since Angle C is 60 degrees that makes angle CAB = 30 degrees
Triangle CAB is a 30 60 90 triangle so line CB is half the hypotenuse or 5 cm
Line BD equals 9 cm
Line AB^2 = 10^2 - 5^2 = 75
Line AD^2 = AB^2 + BD^2
Line AD^2 = 75 + 81
Line AD^2 = 156
Line AD = 12.4899959968
Line AB = Sqr root (75) = 8.6602540378
Angle D = arc sine (8.6602540378 / 12.4899959968)
Angle D = 43.898 degrees
Angle A = 180 - 60 - 43.898 = 76.102 degrees
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Actually this could have been done a little easier by using the Law of Cosines and then the Law of Sines, but I just thought I'd show another way to solve this.
Step-by-step explanation:
Answer:
14,1 cm
Step-by-step explanation:
If a circle passes through the vertices of a square then the diagonal of a square is a circle diameter.
We use Pytagoras Theorem to find out the length (L) of the diagonal given that:
L² = (20)² + (20)²
L² = 2* (20)²
L = √2 * 20
L = 1,4142* 20
L = 28,28 cm
L diagonal in the square is a diameter of the circle then radius of a circle is:
r = L/2 ⇒ r = 28,28 /2 ⇒ r = 14,14 cm
Answer:
8
Step-by-step explanation: