You need to find points where the line g(x) intercepts the quadratic function f(x) in one and only one point.
Then 3x^2 + 4x -2 = mx - 5
solve 3x^2 + 4x - mx -2 + 5 = 0
3x^2 + (4 - m)x + 3 = 0
In order to there be only one solution (one intersection point) the radicand of the quadratic formula must be 0 =>
b^2 - 4ac = (4 - m)^2 - 4(3)(3) = 0
(4 - m)^2 = 24
4 - m = +/- √(24)
m = 4 +/- √(24) = 4 +/- 2√(6)
Then m, the slope of the line, may be 4 + 2√6 and 4 - 2√6
Answer:
A. Angle 1 and Angle 7
Step-by-step explanation:
Those two are the only angles that when added up, the sum is 180.
Angle 7 and Angle 2 are also congruent, so if Angle two forms a straight line with Angle 1, Angle 7 should be able to do that too.
Answer:
$44
Step-by-step explanation:
Use formula
% out of 100/100% = part/whole
20%/100 = 12/16+x
Cross multiply
(12)(100) = (20)(16+x)
1200=320+20x
Solve for x
1200-320 = 20x
880 = 20x
880/20 = x
44 = x
Jim's lunch was $44.
