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victus00 [196]
4 years ago
9

A poster has an area of 1,080 square inches. The poster is 36 inches tall. What is the width of the poster in inches?

Mathematics
1 answer:
nordsb [41]4 years ago
6 0
W=30
Area = L*w
L = 36
36*w=1080
to find the answer, divide 1080 by 36.
You will get 30.
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Question 2 (Multiple Choice Worth 5 points)
steposvetlana [31]
Number of remaining rose cards = 6
number of remaining cards = 8
P(rose card) = 6/8

P(blue marble) = 18/50
P(tail) = 30/50
P(blue marble and tail) = 18/50 x 30/50 = 540/2500
6 0
4 years ago
Find the vertices and foci of the hyperbola with equation quantity x minus five squared divided by eighty one minus the quantity
Papessa [141]
If you notice, the positive fraction, is the one with the "x" variable in it, that simply means, the hyperbola is opening over the x-axis, so is a horizontal one, therefore

\bf \textit{hyperbolas, horizontal traverse axis }
\\\\
\cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h\pm a,  k)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}
\end{cases}\\\\
-------------------------------

\bf \cfrac{(x-5)^2}{81}-\cfrac{(y-1)^2}{144}=1\implies \cfrac{(x-5)^2}{9^2}-\cfrac{(y-1)^2}{12^2}=1~~
\begin{cases}
a=9\\
b=12
\end{cases}
\\\\\\
c=\sqrt{9^2+12^2}\implies c=15\\\\
-------------------------------\\\\
vertices~~(5\pm 9,1)\implies 
\begin{cases}
(14,1)\\
(-4,1)
\end{cases}~~foci~~(5\pm 15,1)\implies 
\begin{cases}
(20,1)\\
(-10,1)
\end{cases}
3 0
3 years ago
I need help i dont understand it. its due in literally 2 hrs.
k0ka [10]

Answer:

$1.25&75

Step-by-step explanation:

8 hotdogs for 10 dollars =

1 hotdog for 1.25 dollars.

1.25×60 = 75

4 0
3 years ago
96,470,000 scientific notation.
Cloud [144]

You're moving the decimal 7 places to the left so the answer is 9.647 x 10^7

8 0
3 years ago
Read 2 more answers
8/10 divided by 1 5/6
LekaFEV [45]
24/55 is the answer 
You can either use a calculator on your phone or computer 
8 0
3 years ago
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