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Effectus [21]
3 years ago
12

The math department recently purchased new learning software for their freshman math classes. The instructors want to use the le

arning software instead of a textbook. So they decide to study the effectiveness of the software. First they test the skills and concept mastery for a number of the freshman math students. Then they randomly divide the students into two groups. One group uses the learning software for a particular lesson and the other group uses the regular textbook. Then the instructors retest all of the students and compare the improvement in the skills and concept mastery for the two groups.what is the purpose of random assignment in this experiment?
Mathematics
1 answer:
Julli [10]3 years ago
6 0

Answer:

The answer about the importance of random selection is recorded in the explanation.

Step-by-step explanation:

The purpose of the random selection of students in two groups is to determine the possible skills that they can develop in the use of the software in a certain time, it could happen that students who stand out for good grades in the area of ​​mathematics do not have good skills in computer science or systems management, as it could happen that students with few skills in mathematics through this tool can clearly understand concepts and develop the exercises with an understanding and ease that perhaps they would not achieve with a textbook.

 Random selection allows an impartial research study to be carried out, revealing essential information for mathematics teachers, making it possible to assess how feasible the use of this new software tool is.

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Please help me by marking the correct answer to each part of number 9. I really dont get this at all, so please tell me why your
natta225 [31]
A. False
Why? Because you cut off the triangle. The measurements are 20 mm and 10 mm.
B. True
Why? Because 20*10 = 200
C. False
Why? Because the base is 6 since 26 - 20 is 6. The height is 4, not 6 because 10 - 6 is 4.
D. True
Why? Because like question C., the base is 6, and the height is 4. 6*4 is 24/2 = 12. If you don't get this, the formula for all triangles is b*h*1/2
E. True
Why? Because from questions B. and D., the area of the rectangle is 200 and the area of the triangle is 12. 200 + 12 = 210.

Hope this helped,
Loafly
3 0
4 years ago
Is 0.35 grater than 300 mL
Sveta_85 [38]

Answer:

yes

Step-by-step explanation:

yes

6 0
3 years ago
Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with
skad [1K]

Parameterize S by the vector function

\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle

The integral of the field over S is then

\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv

\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv

\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}

8 0
2 years ago
Help please thank you very much
Karo-lina-s [1.5K]

Answer:

1.5 miles per day

Step-by-step explanation:

Mr. Turner ran 1.5 miles per day, 4.5 miles / 3 = 1.5 miles.

7 0
3 years ago
Read 2 more answers
Given: MNOK is a trapezoid, MN=OK, m∠M=60°, NK ⊥ MN , MK=16cm Find: The midsegment of MNOK. Need help now will give 15 points
Anastaziya [24]

Answer:  24 unit

Step-by-step explanation:

Here,  MNOK is a trapezoid, MN=OK, m∠M=60°, NK ⊥ MN , MK=16cm

Since, a mid segment is the line segment which joins the mid points of the equal sides of the isosceles trapezoid.

Let LO is the mid segment of trapezoid  MNOK

Where, Let J is the intersection point of KN and LO.

Therefore, LO= LJ+JO --------(1)

And, KL=LO , MO=ON

Since, In triangle KLJ,

∠LKJ=90° ( given),  ∠KLJ=60° ( because, LO║ON and it is given m∠M=60°)

Thus, ∠KJL=30°

Therefore, sin 30°=LK/LJ=8/LJ ( Because ΔMKN is a isoceleus triangle where ∠MKN=∠MNK=30°⇒KM=MN)

⇒LJ=8×2=16

Now, In ΔNOJ,

∠ONJ=∠OJN=30°

Therefore, ON=OJ ( by the property of isosceles triangle)

⇒OJ=8

Thus, By putting these values in equation 1) we get,

LO=16+8=24 cm



7 0
4 years ago
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