Answer:
a) <u><em>y = 9.187 * 1.09899^x</em></u>
b) <u><em>2647.2695</em></u>
Step-by-step explanation:
a) using calculator, (mine is ti84 plus ce), we use stat and edit. we plug in x and y. x will be in the L1 and y wil be in L2. Now, we go to stat, calc, and we press ExpReg, short for exponential regression. we calculate and get <u><em>y = 9.187 * 1.09899^x</em></u>
you can round if you want. well, i guess you shouldn't, cuz it changes it dramatically
b) Now, we use <u><em>y = 9.187 * 1.09899^x </em></u> into the y= and we put it in whatever slot we want. Now, we press trace. we press 60 to find the y,because the number is always x. the number , y, we want is <u><em>2647.2695</em></u> recommendations.
9514 1404 393
Answer:
A. G(x) = ∛(x -1) +1
Step-by-step explanation:
The transformation f(x-h) +k represents a translation (right, up) by (h, k) of the parent function f(x).
Your translation of f(x) = ∛x by (1, 1) will give you the function ...
G(x) = ∛(x -1) +1
<h2>Answer: 250 Hamburgers sold</h2><h2>Step-by-step explanation:</h2><h2><u><em>x = hamburgers
</em></u></h2><h2><u><em>y = cheeseburgers
</em></u></h2><h2><u><em>x+y=434
</em></u></h2><h2><u><em>66 fewer cheeseburgers than hamburgers
</em></u></h2><h2><u><em>
</em></u></h2><h2><u><em> </em></u></h2><h2><u><em>y = x - 66
</em></u></h2><h2><u><em>Substitute y into the first equation
</em></u></h2><h2><u><em>x + (x-66) = 434
</em></u></h2><h2><u><em>2x = 434 + 66
</em></u></h2><h2><u><em>2x = 500
</em></u></h2><h2><u><em>x = 250 hamburgers sold</em></u></h2>
2 = 7 r statement
2/7 = r divide both sides by 7
Step-by-step explanation:
Using the Intermediate Value Theorem, the following is applied:
"If f(x) is a continuous on interval [a,b] and we have two points f(a) and f(b) then there must be some value c such that f(a)<f(c)<f(b).
So here there must be a c such that
Note: F(c)=0, the questions that the function have a solution between 0 and 1, so that means we must have some value, c such that f(c)=0 that exists
Next, plug in the x values into the function
Since cubic functions are continuous and -4<0<4, then there is a solution c that lies between f(0) and f(1)
