Pratibha spends 5 3/4 hours in school. He spends 4 1/4 hours for classes and 3/4 hours for lunch break. She spends the remaining
1 answer:
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Answer:
r = 1/2
c1 = 3/4
c2 = 27/64
c3 = 405/1408
Step-by-step explanation:
Find the solution of 4x2y′′−4x2y′+y=0,x>04x2y″−4x2y′+y=0,x>0 of the form y1=xr(1+c1x+c2x2+c3x3+⋯)
r = 1/2
c1 = 3/4
c2 = 27/64
c3 = 405/1408
The solution is attached.
