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Kazeer [188]
3 years ago
11

Clare solved the inequality below and got an answer of x < -5. Do you agree or disagree with her

Mathematics
1 answer:
Inessa05 [86]3 years ago
4 0

Answer:

Disagree Hope that helps bye !

Step-by-step explanation:

-8x less than 46-6 sub 6 from both sides

46-6= 40 -8x less than 40

x greater than - 40/8 Divide both sides by -8= -5

so it would be x greater than -5 it's disagree because the symbols are different it supposed to be x greater than -5 not less than.

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What is the greatest common factor of 42a5b3, 35a3b4, and 42ab4?
tiny-mole [99]

For this case we have that by definition, the Greatest Common Factor (GCF) is the largest factor that 2 numbers have in common.

So, we have the following expressions:

42a ^ 5b ^ 3\\35a ^ 3b ^ 4\\42ab ^ 4

We look for the positive integers that divide to 35 and 42 without leaving residue:

42: 1,2,3,6,7,14,21

35: 1,5,7

Thus, the GCF of 42 and 35 is 7

Then, the GCF of the three expressions is:

7ab ^ 3

Answer:

7ab ^ 3

4 0
3 years ago
Solve the following equation for g: 2(g-h)=b+4
Vesnalui [34]
<span><span>b=2g-2h-4 
this is correct
</span></span>
3 0
3 years ago
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To make three dozen cookies a recipe calls for four eggs and 3/4 cup of nuts Carlos wants to make tweve dozen cookies how many c
tensa zangetsu [6.8K]

Answer:1/4

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4 0
3 years ago
Find an equation of the line passing through the pair of points. Write the equation in the form Ax +By = C.
Alexxandr [17]

9514 1404 393

Answer:

  5x -y = -37

Step-by-step explanation:

One way to find the coefficients A and B is to use the differences of the x- and y-coordinates:

  A = Δy = y2 -y1 = 2 -(-3) = 5

  B = -Δx = -(x2 -x1) = -(-7 -(-8)) = -1

Then the constant C can be found using either point.

  5x -y = 5(-7) -2 = -37

The equation of the line is ...

  5x -y = -37

_____

<em>Additional comment</em>

This approach comes from the fact that the slope of a line is the same everywhere.

  \dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\Delta y}{\Delta x}\\\\\Delta x(y-y_1)=\Delta y(x-x_1)\qquad\text{cross multiply}\\\\\Delta y(x-x_1)-\Delta x(y-y_1)=0\qquad\text{subtract y term}\\\\\Delta y(x) -\Delta x(y) = \Delta y(x_1)-\Delta x(y_1)\qquad\text{Ax+By=C form}

The "standard form" requires that A be positive, so we chose point 1 and point 2 to make sure that was the case.

5 0
3 years ago
ANSWERED**
den301095 [7]
Yeah if it’s already answered then ima take those points, sorry not sorry g
8 0
3 years ago
Read 2 more answers
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