Suppose you obtained a Spearman rs of 0.53 from a sample of 13 pairs of scores. For a two-tailed test, such a correlation coeffi
1 answer:
Answer:
C: p < 0.01
Step-by-step explanation:
We are given;
Spearman rank Correlation Coefficient: rs = 0.53
sample size: n = 13 pairs
Now, from the table attached, tracing n = 13 and locating a corresponding value of rs = 0.53 which falls in between 0.484 and 0.56. Thus, we can see that p is greater than the nominal significance value of 0.05 but less than 0.01.
Thus, correct answer is p < 0.01
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Option A : is the solution of the equation.
Explanation:
The equation is
To determine the value of x, let us simplify the equation.
Subtracting 5 from both sides of the equation, we have,
Simplifying, we get,
Now , dividing both sides of the equation by 8, we get,
Using the logarithmic definition that if then
Thus, rewriting the above expression using the logarithmic definition, we have,
⇒
Substituting the value of , we get,
Rounding off the answer to two decimal places, we get,
Hence, the solution of the equation is
Therefore, Option A is the correct answer.
Answer:
Step-by-step explanation:
I see you're in college math, so we'll solve this with calculus, since it's the easiest way anyway.
The position equation is
That equation will give us the height of the rock at ANY TIME during its travels. I could find the height at 2 seconds by plugging in a 2 for t; I could find the height at 12 seconds by plugging in a 12 for t, etc.
The first derivative of position is velocity:
v(t) = -3.72t + 15 and you stated that the rock will be at its max height when the velocity is 0, so we plug in a 0 for v(t):
0 = -3.72t + 15 and solve for t:\
-15 = -3.72t so
t = 4.03 seconds. This is how long it takes to get to its max height. Knowing that, we can plug 4.03 seconds into the position equation to find the height at 4.03 seconds:
s(4.03) = -1.86(4.03)² + 15(4.03) so
s(4.03) = 30.2 meters.
Calculus is amazing. Much easier than most methods to solve problems like this.