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3 years ago

What is the quotient of 22,389 ÷ 13? 1,029 R12 1,706 R11 1,722 R3 1,645 R4

Mathematics

2 answers:

Tasya [4]3 years ago

6 0

Answer:

1,722

Step-by-step explanation:

Alenkinab [10]3 years ago

3 0

Answer:

1,722 remainder 3 is the correct answer. I didn't do the problem by hand, but for multiple choice answers, you can always just use a calculator to find the answer and the remainder will be given

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What is the value of (j+3k)(5)?<br><br> j(x) = (x + 4)^2; k(x) = 8 - x<br><br> (j + 3k)(5) =

jeyben [28]

Step-by-step explanation:

J=(x+4)²

K=(8-x)

X=5

=J+3k

=(x+4)(x+4)+3(8-x)

=(x²+8x+16+24-3x)

=25+25+40

=90

Alternatively:

J=(5+4)²

J=81

K=8-5

K=3

J+3k

81+3(3)

81+9

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3 years ago

This is due in a hour

Dimas [21]

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r= radius

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2 years ago

What is 0 divided by 0

Masteriza [31]

Answer:

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8 0

3 years ago

Please help me with this

Arturiano [62]

Answer:

Step-by-step explanation:

4 0

3 years ago

The gravitational force exerted by the planet Earth on a unit mass at a distance r from the center of the planet is:

jolli1 [7]

Answer:

Yes, F is a continuous function of r

Step-by-step explanation:

We are given that

When r<R

$F(r)=\frac{GMr}{R^3}$

$r\geq R$

$F(r)=\frac{GM}{r^2}$

Where M=Mass of the earth

R=Radius of earth

G=Gravitational constant

We have to find the function is continuous of r or not.

LHL

$\lim_{r\rightarrow R-}\frac{GMr}{R^3}=\frac{GMR}{R^3}=\frac{GM}{R^2}$

RHL

$\lim_{r\rightarrow R+}\frac{GM}{R^2}=\frac{GM}{R^2}$

$F(R)=\frac{GM}{R^2}$

When a function is continuous at x=a

Then, LHL=RHL=f(a)

RHL==LHL=F(R)

Hence, the function is continuous of r.

8 0

3 years ago