Suppose that 10% of all steel shafts produced by a process are nonconforming but can be reworked (rather than having to be scrap
1 answer:
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The picture in the attached figure
we know that
the total capacity of the storage container=volume of a cone+volume of cylinder
step 1
find the volume of a cone
volume of a cone=(1/3)*pi*r²*h
r=6 m
h=8 m
so
volume=(1/3)*pi*6²*8-----> 301.44 m³
step 2
find the volume of the cylinder
volume of a cylinder=pi*r²*h
r=6 m
h=10 m
s6
volume=pi*6²*10----> 1130.40 m³
total volume=301.44+1130.4-----> 1431.84 m³-------> 1400 m³
the answer is
1400 m³
we know that
the total capacity of the storage container=volume of a cone+volume of cylinder
step 1
find the volume of a cone
volume of a cone=(1/3)*pi*r²*h
r=6 m
h=8 m
so
volume=(1/3)*pi*6²*8-----> 301.44 m³
step 2
find the volume of the cylinder
volume of a cylinder=pi*r²*h
r=6 m
h=10 m
s6
volume=pi*6²*10----> 1130.40 m³
total volume=301.44+1130.4-----> 1431.84 m³-------> 1400 m³
the answer is
1400 m³