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damaskus [11]
3 years ago
7

.solve for c c−1.5+6.8=0.6 I NEED HELP

Mathematics
1 answer:
kiruha [24]3 years ago
4 0

Answer: c= -4.7

Step-by-step explanation:

Look at link hope it helps

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If p is a positive integer, and 4 is the remainder when p-8 is divided by 5, which of the following
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<h2>sorry I can't help you to solve the equation</h2>
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1. What is the minimum value of y in the graph below<br> y
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-1

Step-by-step explanation:

3 0
3 years ago
1 2 3 4 5 6 7 8 9 10 TIME REMAINING 52:51 Use the data set to determine which statements are correct. Check all that apply. 35,
Nady [450]

Answer:

The true statements are:

  • The median is 38.5.
  • There is an outlier.
  • The lower quartile is 29.
  • The upper quartile is 70.
  • The interquartile range is 41.

Step-by-step explanation:

The given data are:  35, 41, 18, 75, 36, 21, 62, 29, 154, 70

Make the data in order from the least to the greatest

18 , 21 , 29 , 35 , <u>36 , 41</u> , 62 , 70 , 75 , 154

So, the median of the data = (36 + 41)/2 = 38.5

We can deduce that The number 154 represents an outlier because the difference between 154 and 75 is much greater than the difference between the other data

If we divided the data to two groups , they will be:

(18 , 21 , <u>29 </u>, 35 , 36)  ,  (41 , 62 , <u>70 </u>, 75 , 154)

So, The lower quartile Q1 is the median of the first group = 29

And the upper quartile Q2 is the median of the second group = 70

And the interquartile range = Q2 - Q1 = 70 - 29 = 41

So, the true statements are:

  • The median is 38.5
  • There is an outlier
  • The lower quartile is 29
  • The upper quartile is 70
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7 0
3 years ago
The students in Class A and Class B were asked how many pets they each have. The dot plots below show the results. What is the d
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Answer:

2

Step-by-step explanation:

The range of class A is 5-0 = 5

The range of class B is 3-0 = 3

the difference between 3 and 5 is 2.

7 0
3 years ago
Read 2 more answers
Would really appreciate it... will mark brainliest
d1i1m1o1n [39]

Exponential growth would include, A = 20,000(1.08)^t, A=40(30), P=1700(1.07).

Decay would include, A=80(1/2)^t, A= 1600(.8), P=1700(.93)

Hope this helps.

5 0
3 years ago
Read 2 more answers
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