The square root of 13 is an irrational number so you would just write it as the square root of 13.
The next step is to solve the recurrence, but let's back up a bit. You should have found that the ODE in terms of the power series expansion for


which indeed gives the recurrence you found,

but in order to get anywhere with this, you need at least three initial conditions. The constant term tells you that

, and substituting this into the recurrence, you find that

for all

.
Next, the linear term tells you that

, or

.
Now, if

is the first term in the sequence, then by the recurrence you have



and so on, such that

for all

.
Finally, the quadratic term gives

, or

. Then by the recurrence,




and so on, such that

for all

.
Now, the solution was proposed to be

so the general solution would be


Answer: B) (-x, y)
<u>Step-by-step explanation:</u>
If a coordinate is reflected across the y-axis, the y-coordinate stays the same but the x-coordinate changes signs.
Consider (1, 2) as the original point. Now reflect it across the y-axis. The new coordinate is (-1, 2). The y-coordinate stayed the same (2) but the x-coordinate changed signs (1 → -1).
Is it 2 times x squared (2x^2?
2 * 6^2
2 * 36
72
Answer:
7/12
Step-by-step explanation:
12/12-5/12=7/12