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Gala2k [10]
3 years ago
14

A circle has a central angle measuring 90° that intersects an arc of length 117.75 in. What is the length of the radius of the c

ircle?
Mathematics
1 answer:
notka56 [123]3 years ago
7 0
<span>arc length   =   2 * radius * PI * [central angle (degrees) ÷ 360]
</span>
radius = arc length / 2 * PI * .25
radius =117.75 / .5 * PI
radius = <span> <span> <span> 74.9619781963 inches</span></span></span>
Source:
<span><span><span> </span> </span> </span> http://www.1728.org/radians.htm


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I really need the help please and thank you
eimsori [14]

Asnwer: C

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3 0
3 years ago
Do more than 50 percent of the children in a certain group have brown hair?
babymother [125]

Answer:

What we know is that 30% of the group have brown hair and are girls. It means that in the other 70% we have the boys with brown hair, the other boys and the other girls.

In the case all the girls have brown hair, the 70% remaining would be boys. So 70% of then would have brown hair. (0.7*0.7=0.49 -> 49% of the children would be brown hair) so 49% (boys) and 30% (girls) are more than 50%..

Now, let's suppouse that 90% of the group are girls. It means 10% are boys and 70% of that 10% (=7%) are the boys in the group that have brown hair. Now 7% + 30% of the children have brown hair, wich isn't more than the half.

We have explained with two extreme cases that the information is not enough for making a precise answer

7 0
3 years ago
There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=
yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
3 years ago
‼️‼️solve by substitution {-r+T=5 , -2r+T=4. all these problems w work shown (along w the other problems i posted) r due in the
Luden [163]

Answer:

#4: (r,t) = (1,6) #5: (x, y) = (-\frac{1}{2},4) #6: (x, y) = (3, 5) #7: (p, r) = (10,\frac{14}{3} )

Step-by-step explanation:

#4:

Solve for t.

t = 5 + r

Substitute the given value of t into equation

-2r + 5 + r = 4

Solve for r

r = 1

substitute the given value of r into equation

t = 5 + 1

solve for t

t = 6

solution is ordered pair (r, t) = (1,6)

#5:

Solve for y.

y = 2 - 4x

Substitute the given value of y into equation

2x - (2- 4x) = -5

Solve for x

x = - \frac{1}{2}

substitute the given value of x into equation

y = 2 - 4x (- \frac{1}{2})

solve for y

y = 4

solution is ordered pair (x, y) = (-\frac{1}{2},4)

#6:

Solve for x

x = -12 + 3y

Substitute the given value of x into equation

2 (-12 + 3y) + y = 11

Solve for y

y = 5

substitute the given value of y into equation

x = -12 + 3 x 5

solve for x

x = 3

solution is ordered pair (x, y) = (3, 5)

#7

Solve for r

r = \frac{14}{3}

Substitute the given value of  into equation

-2p + 3x \frac{14}{3}  = -6

Solve for p

p = 10

solution is ordered pair (p, r) = (10,\frac{14}{3} )

5 0
3 years ago
Help please!!!!! Correct answer ?
natima [27]

Answer:

go to google

Step-by-step explanation:

go online and type google

3 0
3 years ago
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