Answer:
6.7% of children who finished the race in under 45 seconds.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 75 seconds
Standard Deviation, σ = 20 seconds
We are given that the distribution of time of completion is a bell shaped distribution that is a normal distribution.
Formula:
P(finished the race in under 45 seconds.)
P(x < 45)
Calculation the value from standard normal z table, we have,
6.7% of children who finished the race in under 45 seconds.
Answer: D. -0.6
Step-by-step explanation:
Z score formula= x-mean/ SD
34-40/10= -3/5= -0.6
Answer:
the revenue recognized is $1,275
Step-by-step explanation:
The computation of the revenue recognized is shown below:
= Number of boxes of strawberries sold to customers × price per box
= 85 boxes × $15
= $1,275
Hence, the revenue recognized is $1,275
We simply applied the above formula and the same should be considered
Also
= 130 - 85
= 45 boxes would not be recognized as sale is not made
We set up the equation 580/4 = 725/x. Since we know these are proportional, we can cross-multiply and solve to get x = 5.
The tension in both cables are calculated as; T₁ = 127.63 N and T₂ = 185.48 N
<h3>How to find the Tension in Suspended Cables?</h3>
Resolving forces in the y direction gives us;
T₁ sin 29° + T₂ sin 53° = 210 ------(eq 1)
Resolving forces in the horizontal direction gives;
T₁ cos 29° = T₂ cos 53° ----(eq 2)
T₁ = T₂ cos 53°/cos 29°
Thus;
(T₂ cos 53°/cos 29°)sin 29° + T₂ sin 53° = 210
0.3336T₂ + 0.7986T₂ = 210
T₂ = 210/1.1322
T₂ = 185.48 N
Thus;
T₁ = 185.48 cos 53°/cos 29°
T₁ = 127.63 N
Read more about Tension in Cables at; brainly.com/question/11653585
#SPJ1
