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3 years ago

5-x= 3. work out the value of 3x^2

Mathematics

2 answers:

lbvjy [14]3 years ago

6 0

NVM

Step-by-step explanation:

Xelga [282]3 years ago

3 0

Answer:

If x =2, then 3x^2 equals 12 :D

Step-by-step explanation:

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If a1 = 4 and an -4an-1 then find the value of an.

IRISSAK [1]

1 = 4
-4an - 1

-4an -(4)
an 1

7 0

2 years ago

Please helpppppppppppppppp

Zina [86]

Answer:

29520728184915396206153835295

3 0

2 years ago

In △ABC, ∠ABC = 60 degrees .

ira [324]

A given shape that is bounded by three sides and has got three internal angles is referred to as a triangle. Thus the value of PB is 8.0 units.

A given shape that is bounded by three sides and has got three internal angles is referred to as a triangle. Types of triangles include right angle triangle, isosceles triangle, equilateral triangle, acute angle triangle, etc. The sum of the internal angles of any triangle is $180^{o}$ .

In the given question, point P is center of the given triangle such that <APB = <APC = <BPC = $120^{o}$ . Such that line PB bisects <ABC into two equal measures of $30^{o}$ .

Thus;

<ABP = $30^{o}$

Thus,

<ABP + <APB + <BAP = $180^{o}$

30 + 120 + <BAP = $180^{o}$

<BAP = $180^{o}$ - 150

<BAP = $30^{o}$

Apply the Sine rule to determine the value of PB, such that;

$\frac{a}{SinA}$ = $\frac{b}{SinB}$

$\frac{8}{Sin 30}$ = $\frac{PB}{Sin 30}$

BP = $\frac{8*Sin 30}{Sin 30}$

= 8

BP = 8.0

Therefore, the value of PB = 8 units.

For more clarifications on Sine rule, visit: brainly.com/question/27174058

#SPJ1

5 0

1 year ago

The opposite of which number is closest to -5

Oliga [24]

The answer would be positive 5

8 0

2 years ago

insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of

ss7ja [257]

Answer: $(13.22\%,\ 19.34\%)$

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : $\hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628$

$=16.28\%$

Significance level : $\alpha= 1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

Confidence level for population proportion:-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)$

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= $(13.22\%,\ 19.34\%)$

7 0

3 years ago