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umka2103 [35]
3 years ago
6

Which equation can be used to find the answer? 

Mathematics
2 answers:
Arada [10]3 years ago
7 0
The answer would be D
Lera25 [3.4K]3 years ago
7 0
<span>  
B. 
f – 18.7 = 29 
f = 47.7 
47.7 m
</span>
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Adelaide paid $35 for a manicure and gave the manicurist a 20% tip.
Nikolay [14]
That would be 35 + 0.20*35  =  $42
7 0
3 years ago
There are 25 students that would like to go on a field trip, but only 18 may go. How many different combinations of students cou
Naya [18.7K]

480700. The different combinations of students that could go on the trip with a total of 25 student, but only 18 may go, is 480700.

The key to solve this problem is using the combination formula nC_{r}=\frac{n!}{r!(n-r)!}. This mean the number of ways to choose a sample of r elements from a set of n distinct objects where order does not matter and replacements are not allowed.

The total of students is n and the only that 18 students may go is r:

25C_{18}=\frac{25!}{18!(7!)}=480700

6 0
3 years ago
Write an equation in slope-intercept form that is parallel to the line 3x + 2y = 1 and passes through the point (1, 0). A)
Lunna [17]

Answer:

D) y = − 3/2 x + 3 /2

Step-by-step explanation:

3x+2y =1

We need to get this in slope intercept form (solve for y)

Subtract 3x from each side

3x-3x +2y = -3x+1

2y = -3x+1

Divide by 2

2y/2 = -3/2x+1/2

The slope is -3/2

We want a line that is parallel so the slope is the same

m = -3/2

We an use point slope form since we have the slope and a point

y - y1 = m(x-x2)

y - 0 = -3/2(x-1)

Distribute

y = -3/2x +3/2

7 0
4 years ago
Read 2 more answers
Given sin x = -4/5 and x is in quadrant 3, what is the value of tan x/2
love history [14]

bearing in mind that, on the III Quadrant, sine as well as cosine are both negative, and that hypotenuse is never negative, so, if the sine is -4/5, the negative number must be the numerator, so sin(x) = (-4)/5.


\bf sin(x)=\cfrac{\stackrel{opposite}{-4}}{\stackrel{hypotenuse}{5}}\impliedby \textit{let's find the \underline{adjacent}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2-(-4)^2}=a\implies \pm\sqrt{9}=a\implies \pm 3=a \\\\\\ \stackrel{III~Quadrant}{-3=a}~\hfill cos(x)=\cfrac{\stackrel{adjacent}{-3}}{\stackrel{hypotenuse}{5}} \\\\[-0.35em] ~\dotfill

\bf tan\left(\cfrac{\theta}{2}\right)= \begin{cases} \pm \sqrt{\cfrac{1-cos(\theta)}{1+cos(\theta)}} \\\\ \cfrac{sin(\theta)}{1+cos(\theta)}\qquad \leftarrow \textit{let's use this one} \\\\ \cfrac{1-cos(\theta)}{sin(\theta)} \end{cases} \\\\[-0.35em] ~\dotfill

\bf tan\left( \cfrac{x}{2} \right)=\cfrac{~~\frac{-4}{5}~~}{1-\frac{3}{5}}\implies tan\left( \cfrac{x}{2} \right)=\cfrac{~~\frac{-4}{5}~~}{\frac{2}{5}}\implies tan\left( \cfrac{x}{2} \right)=\cfrac{-4}{5}\cdot \cfrac{5}{2} \\\\\\ tan\left( \cfrac{x}{2} \right)=\cfrac{-4}{2}\cdot \cfrac{5}{5}\implies tan\left( \cfrac{x}{2} \right)=-2

4 0
4 years ago
Read 2 more answers
Eve is replacing the soil in her plant containers. How many cubic inches of soil will Eve need for the two rectangular contain
sveta [45]
The answer is B, 216in 3.
8 0
4 years ago
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