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s344n2d4d5 [400]
3 years ago
11

PLEASE HELP :)))))))))))))

Mathematics
1 answer:
solong [7]3 years ago
6 0

Answer:

62 sorry if i am wrong please dont report

Step-by-step explanation:

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I need help plz answer as soon as possible
Gekata [30.6K]

Answer:

x = 7

Step-by-step explanation:

Let's join A & C . If points A ,B & C are collinear , then definitely B point's gonna lie on line segment AC .

So , AC = AB + BC

In the question , length of AC = 3x + 3 , length of AB = 2x - 1 ( or -1 + 2x)

& length of BC = 11.

We know that AC = AB + BC . So putting the given values here :-

3x+3 = 2x -1 + 11\\=>3x +3 = 2x+10\\

Solving this linear eqn. gives

3x + 3=2x+10\\=> 3x-2x=10-3\\=>x=7

4 0
3 years ago
9(x + 8) + 11(3x + 4)
Sav [38]
Simplify the expression : 42x + 116

Hope this helps!
Have a great day!

5 0
3 years ago
Determine whether the binomial is a factor of f(x).<br><br> f(x) = x3 + 11x2 + 24x - 36; x - 4
attashe74 [19]
If it is, then f(4) would be equal 0.

f(4)=4^3+11\cdot4^2+24\cdot4-36\\&#10;f(4)=64+11\cdot16+96-36\\&#10;f(4)=124+176\\&#10;f(4)=300\not =0 \Rightarrow \text{ it isn't}
8 0
3 years ago
Steve is turning half his backyard into a chicken fan. His backyard is a 24 m x 45 m rectangle. He wants to put a chicken wire f
Phoenix [80]

Answer:

51 meters

Step-by-step explanation:

Steve is turning half his backyard into a chicken fan. His backyard is a 24 m x 45 m rectangle. He wants to put a chicken wire fence that stretches diagonally from one corner to the opposite corner. How many meters of fencing will Steve need?

We are to find the meters of fencing for the diagonal.

We solve the question using Pythagoras Theorem

= c² = a² + b²

Where

c = Diagonal

a = Width

b =Length

Diagonal² = Width² + Length ²

Hence:

Diagonal ² = 45² + 24²

Diagonal = √45² + 24²

Diagonal = √(2601)

Diagonal = 51 m

Therefore, the meters of fencing for the diagonal that Steve would be needing = 51 meters

7 0
3 years ago
There are 40 girls and 60 boys in the math club the coach wants to divide the entire club into teams where each team has the sam
lapo4ka [179]
40 and 60
40 = 20 x 2
60 = 20 x 3

GCF = 20

<span>the greatest number of teams coach can make is 20
each team can have 2 girls and 3 boys</span>
6 0
3 years ago
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