Answer:
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no one help you this is bad app hahahahaha
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
HMMMMMMM...It could be C...
An Arc is the the end of the circle, the OUTER rim..do you get what I'm trying to say? SO, if you look at AC, it looks like an arc.
Hope this helps!
P=5000
t=8
r=7%=0.07
n=4
Now all of this have to be substituted to the formula
A=5000(1+0.07/4)^(4*8)=5000(1+0.07/4)³²=8711.07
