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3 years ago

[8-(-12)]÷(2x-2)-(-8)

Mathematics

1 answer:

WITCHER [35]3 years ago

6 0

Answer:

Step-by-step explanation:

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Select the simplification that accurately explains the following statement.

lutik1710 [3]

Answer:

Option (b) is correct.

$(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}=2^{1}=2$

Step-by-step explanation:

Given: $(2^\frac{1}{4} )^4$

We have too choose the correct simplification for the given statement.

Consider $(2^\frac{1}{4} )^4$

Using property of exponents, $(a^m)^n=a^m\times a^m\times a^m\times ....\times (n\ times)$

We have,

$(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}$

Again applying property of exponents $a^m\times a^m=a^{n+m}$

We have,

$(2^\frac{1}{4} )^4=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}$

Simplify, we have,

$(2^\frac{1}{4} )^4=2^{\frac{4}{4}}$

we get,

$(2^\frac{1}{4} )^4=2^{1}=2$

Thus, $(2^\frac{1}{4} )^4=2$

Option (b) is correct.

8 0

3 years ago

Read 2 more answers

you have 120 pieces of fabric to make a blanket. each piece of fabric is a square with a side length of 6 inches. you use as man

guapka [62]

To make a square blanket, you need to calculate the squareroot of 120, which is 10,954... so the biggest number is 10x10 peaces of fabric you can use to create a square blanket. These are 100 (so 20 are left over). To create a bigger square blanket of 11×11 peaces (11^2 = 121) you need one more peace of fabric. One peace is six inches, the blanket is 10 peaces long (6×10=60) The size would be 60inchesx60inches= 3.600 inches.

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3 years ago

Whats the equation of the line given f(3)=5 and f(7)=9

Ksju [112]

Use symbols.com as it helps me

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3 years ago

Jerome found the lengths of each side of triangle QRS as shown, but did not simplify his answers. Simplify the lengths of each s

emmainna [20.7K]

Answer:

Triangle QRS is an isosceles triangle because QR = RS.

Step-by-step explanation: