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labwork [276]
3 years ago
12

Which of the following points is a solution of the inequality y < |x - 2|?

Mathematics
1 answer:
crimeas [40]3 years ago
3 0

Answer:

(-2,0)

Step-by-step explanation:

y < |x - 2|

Substitute the points in and check

(-2,0)

0 < |-2 - 2|

0 < |-4|

0 < 4  True

(2,1)

1 < |2 - 2|

1 < |0|

1 < 0  False

(2,0)

0 < |2 - 2|

0 < |0|

0 < 0 False

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Find the volume of the wedge-shaped region contained in the cylinder x2 + y2 = 49, bounded above by the plane z = x and below by
fiasKO [112]
\displaystyle\iiint_R\mathrm dV=\int_{y=-7}^{y=7}\int_{x=-\sqrt{49-y^2}}^{x=0}\int_{z=x}^{z=0}\mathrm dz\,\mathrm dx\,\mathrm dy

Converting to cylindrical coordinates, the integral is equivalent to

\displaystyle\iiint_R\mathrm dV=\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}\int_{z=r\cos\theta}^{z=0}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle\int_{\theta=\pi/2}^{\theta=3\pi/2}\int_{r=0}^{r=7}-r^2\cos\theta\,\mathrm dr\,\mathrm d\theta
=-\displaystyle\left(\int_{\theta=\pi/2}^{3\pi/2}\cos\theta\,\mathrm d\theta\right)\left(\int_{r=0}^{r=7}r^2\,\mathrm dr\right)
=\dfrac{2\times7^3}3=\dfrac{686}3
4 0
3 years ago
20. Based on student records, 25% of the students at a large high school have a
Elenna [48]

Answer:

(E) 0.71

Step-by-step explanation:

Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.

So, the  probability that the student has a GPA lower than 3.5 and is not taking any AP  classes is calculated as:

P(A'∩B') = 1 - P(A∪B)

it means that the students that have a GPA lower than 3.5 and are not taking any AP  classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.

Therefore, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled  in at least one AP class is 0.12

So, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(A∪B) = 0.25 + 0.16 - 0.12

P(A∪B) = 0.29

Finally, P(A'∩B') is equal to:

P(A'∩B') = 1 - P(A∪B)

P(A'∩B') = 1 - 0.29

P(A'∩B') = 0.71

5 0
3 years ago
Read 2 more answers
What Is The Similarity Between 85,17,19,4,2
aalyn [17]
If a(n) = (39n^4 -506n^3 + 2341n^2 - 4610n + 3416) / 8 then 

<span>a(1) = 85 </span>
<span>a(2) = 17 </span>
<span>a(3) = 19 </span>
<span>a(4) = 4 </span>
<span>a(5) = 2</span>
8 0
3 years ago
A baker uses 1,232 ounces of flour daily. The baker's recipe for a loaf of bread calls for 12 ounces of flour. How many full loa
VashaNatasha [74]

Answer:

102 loafs of bread

Step-by-step explanation:

1232 ÷ 12 = 102.6666666666

102 is the answer

5 0
3 years ago
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In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. The side lengths o
ycow [4]

Answer:

A

Step-by-step explanation:

In the figure shown, ABC is a right triangle with side lengths a, b, and c, and CD is an altitude to side AB. This altitude divides the triangle into two right triangles ADC and BDC. In these triangles,

  • \angle CBD\cong \angle ACD\cong \angle CBA
  • \angle DCB\cong \angle DAC\cong \angle BAC

So,

\triangle ABC\sim \triangle CBD\sim \triangle ACD

1. From the similarity \triangle ABC\sim \triangle CBD, you have

\dfrac{AB}{BC}=\dfrac{BC}{BD}\\ \\\dfrac{c}{a}=\dfrac{a}{s}

2. From the similarity \triangle ABC\sim \triangle ACD, you have

\dfrac{AB}{AC}=\dfrac{AC}{AD}\\ \\\dfrac{c}{b}=\dfrac{b}{r}

Hence, option A is true

5 0
3 years ago
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