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valkas [14]
3 years ago
8

Can someone plz help me with this and explain how to do this math problem

Mathematics
1 answer:
Viktor [21]3 years ago
7 0

Answer:

greater

Step-by-step explanation:

the reason is because if you allow x to have a value that is less than 3,

\sqrt{x - 3}

will produce a square root of a negative number, and the square root of a negative number requires the use of imaginary numbers, therefore limiting x to greater than or equal to 3 prevents this, also, consideration should be given to the fraction

\frac{3}{x + 2}

if x has a value of -2 it causes the denominator of the fraction to be 0, the denominator should never be 0, by limiting x to greater than 3 to prevent the problem above you are already taking care of x not being able to be -2 since greater than 3 already excludes -2

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yawa3891 [41]

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