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marysya [2.9K]
3 years ago
15

Pretty heart I love this song soo much

Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Answer:

i made this poem

Step-by-step explanation:

Send this to anyone that feels left out or you love please.

No Need to be a shadow i see you

No need to be muted i can hear you

No need to cut your not paper

No need to Hang your not a coat

No need to Fall apart because of a guy you'll soon find better

No need to play with your life You are not a toy

No need to not feel loved I love you

No need to feel Numb I'm here

No need to pop pills Your loved

No need to Commit suic.ide There is to much to life

I think all I'm saying is Life is Way more then school, job, rest and repeat There's adventures Happy moments and Horrifying times But we all soon get over these things Your in this world in a life For a reason Life it with a purpose

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5 Exam-style ABCD is a kite.
Mnenie [13.5K]

let's recall that in a Kite the diagonals meet each other at 90° angles, Check the picture below, so we're looking for the equation of a line that's perpendicular to BD and that passes through (-1 , 3).

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of BD

y = \stackrel{\stackrel{m}{\downarrow }}{3}x-1\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line whose slope is -1/3 and passes through point A

(\stackrel{x_1}{-1}~,~\stackrel{y_1}{3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{-\cfrac{1}{3}}[x-\stackrel{x_1}{(-1)}]\implies y-3=-\cfrac{1}{3}(x+1) \\\\\\ y-3=-\cfrac{1}{3}x-\cfrac{1}{3}\implies y=-\cfrac{1}{3}x-\cfrac{1}{3}+3\implies y=-\cfrac{1}{3}x+\cfrac{8}{3}

5 0
2 years ago
Pls let me know what you get for the question below
Fiesta28 [93]

Answer:

233.37

Step-by-step explanation:

so between each gondola is 20.95 so you will multiply it by 35 not 36 (because between the first you go round and come back to the same first you started so no space between first and last) then get circumference as 733.25 using

c = \pi \: d

you get diameter

4 0
3 years ago
Can y'all help me with math I hate it
antoniya [11.8K]

Answer:

Step-by-step explanation:

the first one

6 0
3 years ago
Read 2 more answers
Hey guys I need help on maths. ​
Pepsi [2]

Answer:

x=122°

Step-by-step explanation:

sum of all interior angles in a quadrilateral = 360°

then ,

119+105+78+m = 360

m = 58

....

m+ x = 180 ( linear pair)

58+x = 180

x = 122

4 0
3 years ago
Help!!Need help please help me
irina [24]
 8x-6y=-96  add to this -4 times the second equation...
-8x-12y=-48
___________

-18y=-144

y=8, this makes 8x-6y=-96 become:

8x-48=-96

8x=-48

x=-6

so the solution to the system of equations is the point:

(-6,8)
3 0
3 years ago
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