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charle [14.2K]
3 years ago
14

Find the percent of increase for 4 to 7. round to the nearest tenth if necessary. also someone please explain how to do this.

Mathematics
1 answer:
dem82 [27]3 years ago
8 0

Answer:

75%

Step-by-step explanation:

The percent increase is calculated as

percent increase = \frac{increase}{original number} × 100%

increase = 7 - 4 = 3, thus

% increase = \frac{3}{4} × 100% = \frac{3(100)}{4} = 75%

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If f(x) => x2 +6, what is the value of f(8)?
soldier1979 [14.2K]

Answer:22

Step-by-step explanation: since f(8) so x=8

substitiuting x in 2x+6

                                      f(8)= 2x8+6=22

so f(8)=22

Hope this helps! :)

4 0
2 years ago
What is (6^3)^4 simplified
Sophie [7]

Step-by-step explanation:

( {6}^{3})^{4}   =  {6}^{3 \times 4}  =  {6}^{12} \\

7 0
3 years ago
mr george has a bank balance of 42 dollar at the start of the mouth.after he depostite 6 dollar the new balance is
Lubov Fominskaja [6]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Which equation can pair with x-y=-2 to create a consistent and dependent system?
MrRissso [65]

See the explanation

<h2>Explanation:</h2>

A system that has one or infinitely many solutions is called <em>consistent. </em>If an equation in a system tells us no new information then the equations of the system are <em>dependent. </em>In other words, to find an equation that creates a consistent and dependent system with the given equation we have to get the same line:

The given line is:

x-y=-2

If we multiply both sides of the equation by a constant we will have the same line when plotting, therefore let's multiply by 3:

3(x-y)=3(-2) \\ \\ 3x-3y=-6

So a system of two linear equation that is consistent and dependent is:

\left \{ {{x-y=-2} \atop {3x-3y=-6}} \right.

<h2>Learn more:</h2>

Graph of lines: brainly.com/question/14434483#

#LearnWithBrainly

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Which two points on the number line represent numbers that can be combined to make zero?
AnnZ [28]

Answer:

option (D) is the right answer

6 0
3 years ago
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