Question

Evaluate log38, given log32 ≈ 0.631.

Answer 1

Answer:

1.893

Step-by-step explanation:

$log_3(8)$

first we write 8 in exponential form

8=2*2*2= 2*3

$log_3(2^3)$

Now we apply log property

$log_b(a^n)= n log_b(a)$

As per this property we move the exponent before log

$log_3(2^3)= 3 log_3(2)$

Given log_3(2) = 0.631

Plug in the value

$log_3(2^3)= 3 log_3(2)= 3*0.631= 1.893$

Answer 2

$\log_38-\log_32^3=3\log_32\approx3\cdot0.631=1.893\\\\Used:\log_ab^n=n\cdot\log_ab$