Lol I like your da baby pfp.
Oh, and the answer is y = -4x + 1
Here’s the graph:
Usually called "half of base times height", the area of a triangle is given by the formula below.Area=ba2whereb is the length of the base
a is the length of the corresponding altitude
You can choose any side to be the base. It need not be the one drawn at the bottom of the triangle. The altitude must be the one corresponding to the base you choose. The altitude is the line perpendicular to the selected base from the opposite vertex.
In the figure above, one side has been chosen as the base and its corresponding altitude is shown.
Answer:

Step-by-step explanation:

I drew the segment and used Pythagorean theorem to solve for its measure. The line formed is the hypotenuse of the imaginary right triangle.
Among the choices only -1.33 and -1.25 is a feasible choice. But I am leaning towards -1.25 as the y-value of point F based on my diagram. Please see attachment.
Answer:
- 109°, obtuse
- 131°, obtuse
- 53°, acute
- 124°, obtuse
Step-by-step explanation:
You are exected to know the relationships of angles created where a transversal crosses parallel lines.
- Corresponding angles are equal (congruent).
- Adjacent angles are supplementary, as are any linear pair.
- Opposite interior (or exterior) angles are equal (congruent).
The appearance of the diagram often gives you a clue.
You also expected to know the name (or category) of angles less than, equal to, or greater than 90°. Respectively, these are <em>acute</em>, <em>right</em>, and <em>obtuse</em> angles.
1. Adjacent angles are supplementary. The supplement of the given angle is 109°, so x will be obtuse.
2. Opposite exterior angles are equal, so y will be 131°. It is obtuse.
3. Opposite interior angles are equal, so w will be 53°. It is acute.
4. Corresponding angles are equal, so x will be 124°. It is obtuse.