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RUDIKE [14]
4 years ago
12

Find the two integers, m and n, make the equation (2x^ny2)m = 4x6y4 true.

Mathematics
1 answer:
musickatia [10]4 years ago
3 0

Answer:

m = 2 and n = 3

Step-by-step explanation:

We want to find the value of the integers m and n that will make the given expression true

(2x^ny^2)^m = 4x^6y^4

We can rewrite the left hand side of the equation as follows;

(2x^3y^2)^2

we can proceed to use inspection to ind the value of m and n

Through inspection since the left hand side of the equation now looks like the right hand side;

Then;

m= 2 and n = 3

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Lostsunrise [7]
  • Center =(h,k) = (0,2.25)
  • Radius = r = \frac{14}{13}

<u>Step-by-step explanation:</u>

Here we have following equation : x^{2}+(y-2.25)^{2} = \dfrac{196}{169}

We need to find the center & radius of this circle . Let's find out:

We know that , Equation of a circle is given by :

⇒ (x-h)^2+(y-k)^2=r^2   ........(1)

Here , (h,k) are the co-ordinates of center & r is the radius of circle.Collectively called as a circle with radius r and center at (h,k) . Let's frame given equation in question :

⇒  x^{2}+(y-2.25)^{2} = \frac{196}{169}

⇒  (x-0)^{2}+(y-2.25)^{2} = (\frac{14}{13})^2

On comparing this equation with equation (1) we get :

  • Center =(h,k) = (0,2.25)
  • Radius = r = \frac{14}{13}
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X = y 2 - 1
pochemuha
Your answer would be option B. 2y² - y - 6 = 0. This is because if you were to substitute x = y² - 1 into the equation 2x - y = 4, you would get 2(y² - 1) - y = 4, which expands into 2y² - 2 - y = 4, and then simplifies to 2y² - y - 6 = 0.
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