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3 years ago

Find the two integers, m and n, make the equation (2x^ny2)m = 4x6y4 true.

Mathematics

1 answer:

musickatia [10]3 years ago

3 0

Answer:

m = 2 and n = 3

Step-by-step explanation:

We want to find the value of the integers m and n that will make the given expression true

(2x^ny^2)^m = 4x^6y^4

We can rewrite the left hand side of the equation as follows;

(2x^3y^2)^2

we can proceed to use inspection to ind the value of m and n

Through inspection since the left hand side of the equation now looks like the right hand side;

Then;

m= 2 and n = 3

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