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3 years ago

HELP!!!!!!!!! 10= p x 0.048 x 1/12

Mathematics

1 answer:

Furkat [3]3 years ago

4 0

I hope this helps you

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Please help ASAP 10 points

dimulka [17.4K]

Answer:-4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the distance between these points. R(-1,0), S(8,6) V(26) V(85) 3V(13)

Thepotemich [5.8K]

Answer:

The distance is equal to $3\sqrt{13}\ units$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$R(-1,0)\\S(8,6)$

substitute the values

$d=\sqrt{(6-0)^{2}+(8+1)^{2}}$

$d=\sqrt{(6)^{2}+(9)^{2}}$

$d=\sqrt{36+81}$

$d=\sqrt{117}\ units$

Simplify

$d=3\sqrt{13}\ units$

4 0

3 years ago

4.5w = 5.1w - 30 Please help!!!

Lelu [443]

4.5w = 5.1w - 30

4.5w - 5.1w = -30

-0.6w =-30

Divide both sides by -0.6

-0.6w/-0.6 = -30/-0.6

w = 50

I hope this helps.

6 0

3 years ago

Assume the readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees

lozanna [386]

Answer: 0.0035

Step-by-step explanation:

Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.

i.e. $\mu=0$ and $\sigma= 1$

Let x denotes the readings on thermometers.

Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_

$P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035$

Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035

The required region is attached below .

8 0

2 years ago

Find the length of the segment indicated. Round your answer to the nearest tenth if necessary.

alukav5142 [94]

Answer:

x=5

Step-by-step explanation:

im so bad at explaining things but i hope this helped

3 0

3 years ago