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erica [24]
3 years ago
7

HELP!!!!!!!!! 10= p x 0.048 x 1/12

Mathematics
1 answer:
Furkat [3]3 years ago
4 0
I hope this helps you

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Please help ASAP 10 points
dimulka [17.4K]

Answer:-4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the distance between these points.<br> R(-1,0), S(8,6)<br> V(26)<br> V(85)<br> 3V(13)
Thepotemich [5.8K]

Answer:

The distance is equal to 3\sqrt{13}\ units

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

R(-1,0)\\S(8,6)  

substitute the values

d=\sqrt{(6-0)^{2}+(8+1)^{2}}

d=\sqrt{(6)^{2}+(9)^{2}}

d=\sqrt{36+81}

d=\sqrt{117}\ units

Simplify

d=3\sqrt{13}\ units

4 0
3 years ago
4.5w = 5.1w - 30<br><br> Please help!!!
Lelu [443]
4.5w = 5.1w - 30

4.5w - 5.1w = -30

-0.6w =-30

Divide both sides by -0.6

-0.6w/-0.6 = -30/-0.6

<span>w = 50

</span>I hope this helps.
6 0
3 years ago
Assume the readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees
lozanna [386]

Answer: 0.0035

Step-by-step explanation:

Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.

i.e.  \mu=0 and \sigma= 1  

Let x denotes the readings on thermometers.

Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_

P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035

Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035

The required region is attached below .

8 0
2 years ago
Find the length of the segment indicated. Round your answer to the nearest tenth if necessary.
alukav5142 [94]

Answer:

x=5

Step-by-step explanation:

im so bad at explaining things but i hope this helped

3 0
3 years ago
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