Help please please please:((((
1 answer:
There are no numbers on the graph, so we cannot tell for sure the value of f(3).
If the grid squares are each one unit, then the graph of f(x) appears to go through the grid point (3, -1). This means f(3) = -1.
Using this value in the expression for g(x), we have
.. g(3) = -4*f(3) +7
.. g(3) = -4*(-1) +7
.. = 4 +7
.. = 11
The value of g(3) is 11.
If the grid squares are each one unit, then the graph of f(x) appears to go through the grid point (3, -1). This means f(3) = -1.
Using this value in the expression for g(x), we have
.. g(3) = -4*f(3) +7
.. g(3) = -4*(-1) +7
.. = 4 +7
.. = 11
The value of g(3) is 11.
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Answer:
C
Step-by-step explanation:
Given
The numerator is a difference of squares
x² - 16 = (x - 4)(x + 4)
= ← cancel the common factor (x + 4) on numerator/ denominator
= → C