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3 years ago

So many more questions coming in that means more points

Mathematics

2 answers:

Svet_ta [14]3 years ago

5 0

Answer and Explanation

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<h2>The equation has infinitely many solutions.</h2><h3>( x = an infinite amount of numbers )</h3>

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We can prove this by using multiple numbers into the equation.

Let me show you what I mean.

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$3\left(2x+1\right)=8x+2-2x+1$

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$3\left(2\cdot2+1\right)$ = $15$ ( in this case, x = 2 )

$8\cdot2+2-2\cdot2+1$ = $15$ ( so, x can equal 2, but I checked again if there are multiple answers. )

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$3\left(2\cdot8+1\right)$ = $51$ ( in this instance, x = 8 )

$8\cdot8+2-2\cdot8+1$ = $51$ ( since x = 8 and can equal anything else, my conclusion is, that there are infinitely many solutions. )

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Hope this helps! <3

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mafiozo [28]3 years ago

4 0

Answer:

I think that there are infinitely many solutions

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Question 7 A number cube with faces labeled from 1 to 6 will be rolled once. The number rolled will be recorded as the outcome.

QveST [7]

Answer:

1) $S=\{1,2,3,4,5,6\}$

2) $O=\{1,3,5\}$

Step-by-step explanation:

Given : A number cube with faces labeled from 1 to 6 will be rolled once. The number rolled will be recorded as the outcome.

To find : Give the sample space describing all possible outcomes. Then give all of the outcomes for the event of rolling an odd number. If there is more than one element in the set, separate them with commas ?

Solution :

A number cube with faces labeled from 1 to 6 will be rolled once.

The sample space describing all possible outcomes is given by

$S=\{1,2,3,4,5,6\}$

All of the outcomes for the event of rolling an odd number is given by

$O=\{1,3,5\}$

6 0

3 years ago

I have no clue to what I even need to do.

Gre4nikov [31]

$\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ \cline{1-1} \theta =\frac{3\pi }{2}\\ s=\frac{5\pi }{2} \end{cases}\implies \cfrac{5\pi }{2}=r\cdot \cfrac{3\pi }{2}$

$\bf \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{3~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }\cdot \cfrac{5~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=r\implies \cfrac{5}{3}=r$