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3 years ago

So many more questions coming in that means more points

Mathematics

2 answers:

Svet_ta [14]3 years ago

5 0

Answer and Explanation

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<h2>The equation has infinitely many solutions.</h2><h3>( x = an infinite amount of numbers )</h3>

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We can prove this by using multiple numbers into the equation.

Let me show you what I mean.

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$3\left(2x+1\right)=8x+2-2x+1$

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$3\left(2\cdot2+1\right)$ = $15$ ( in this case, x = 2 )

$8\cdot2+2-2\cdot2+1$ = $15$ ( so, x can equal 2, but I checked again if there are multiple answers. )

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$3\left(2\cdot8+1\right)$ = $51$ ( in this instance, x = 8 )

$8\cdot8+2-2\cdot8+1$ = $51$ ( since x = 8 and can equal anything else, my conclusion is, that there are infinitely many solutions. )

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Hope this helps! <3

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mafiozo [28]3 years ago

4 0

Answer:

I think that there are infinitely many solutions

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strojnjashka [21]

Answer:

u = 1

Step-by-step explanation:

First, we can use inverse operations to help.

27 + 9u = 36

Next, we can start replacing u with numbers to find which number fits in u.

27 + 9(1) = 36

27 + 9(2) ≠ 36

27 + 9(3) ≠ 36

Now, we know that u = 1

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3 years ago

a person on tour has 360 $ for his daily expense. if he extends his tour for 4 days,he has to cut down his daily expense by 3$.

Cloud [144]

Answer:

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Step-by-step explanation:

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3 years ago

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Inga [223]

I remember doing this in 5th grade, maybe 6th.

5. The integer in the problem is 60; 0 represents no money withdrawn.
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3 years ago

What is the next step you should take -11x = -11

RSB [31]

Answer:

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Step-by-step explanation:

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3 years ago

Suppose you first randomly sample one card from a deck of 52. Then, without putting the card back in the deck you sample a secon

Alex787 [66]

Answer:

P(A) = 1201/5525 or 0.2174

The probability that at least one ace will be in the three sampled cards is 1201/5525 or 0.2174

Step-by-step explanation:

Let P(A) represent the probability that at least one ace will be in the three sampled cards.

P(A) = 1 - P(A') ......1

Where;

P(A') is the probability that none of the three cards will be ace.

Number of ace in a standard 52 cards = 4

Number of non-ace in a standard 52 cards = 52-4 =48

P(A') = 48/52 × 47/51 × 46/50

P(A') = 4324/5525 = 0.7826

Substituting, the value into equation 1;

P(A) = 1 - P(A')

P(A) = 1 - 4324/5525

P(A) = 1201/5525 or 0.2174

The probability that at least one ace will be in the three sampled cards is 1201/5525 or 0.2174

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