Question 8
1 answer:
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A segment is bounded by two endpoints.
The two segments can have up to two common points
Assume the line segments are AB and CD where the length of AB is greater than the length of CD.
<u>The possibilities are:</u>
- <em>A point of segment CD lies on segment AB</em>
- <em>Both points of segment CD lie on segment AB.</em>
<em />
See attachment for both possibilities.
Hence, it is possible for the two segments to have two common points.
Read more about line segments at:
Answer:
1. So, it's basically y=mx + b, you put the b first like y= 2/3x -1, and the b is negative, so you go down on the y-axis one time and the 2/3x is rise over run 2 is the rise and 3 is the run.
for y=-x -4 you put a denominator for -x like -1/1x you keep the denominator positive.
2. If the 2x is in the incorrect spot you put it on the other side and it's a positive, so you put is as a negative on the other side, so you're left with
-y=-2x-1, but you can't have a sign on them, so you divide it with -1 and on the other side as well, so it comes down to y=2x+1 and if the x doesn't have a denominator you add a one to it, like this y=2/1x+1 and you put the 1 on the y-axis and its a positive so you go up one time and the rise or run is 2/1, so you start at 1 on the y-axis and you rise 2 times, so 3-axis and run 1 time and it's 1-axis.
For the last one ill do it on paper.
