For the equation: D = -0.306c + 0.9979, what is the value of D when c= 1.67? Express answer with the correct number of sig figs?

Mathematics

1 answer:

Gekata [30.6K]3 years ago

6 0

Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

d=(−0.306)(1.67)+0.9979

Step 1: Simplify both sides of the equation.

d=(−0.306)(1.67)+0.9979

d=−0.51102+0.9979

d=(−0.51102+0.9979) (Combine Like Terms)

d=0.48688

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The answer is 34.05

The total distance (D) is the sum of three distances (d1, d2, and d3).

The distance formula is $d = \sqrt{(x2-x1)^{2} +(y2-y1)^{2}}$

Distance 1: Phoenix (–12, –16) to Blythe (–20, –9)<span>:
</span> $d1 = \sqrt{(-20-(-12))^{2} +(-9-(-16))^{2}} =\sqrt{(-20+12)^{2} +(-9+16)^{2}} \\ =\sqrt{(-8)^{2} +(7)^{2}}= \sqrt{64+49} = \sqrt{113}= 10.63$

Distance 2: Blythe (–20, –9) to Los Angeles (–33, –4):
$d2 = \sqrt{(-33-(-20))^{2} +(-4-(-9))^{2}} =\sqrt{(-33+20)^{2} +(-4+9)^{2}} \\ =\sqrt{(-13)^{2} +(5)^{2}}= \sqrt{169+25} = \sqrt{194}= 13.93$

Distance 3: Los Angeles (–33, –4) to <span>San Francisco (–36, 5)
</span> $d3 = \sqrt{(-36-(-33))^{2} +(5-(-4))^{2}} =\sqrt{(-36+33)^{2} +(5+4)^{2}} \\ =\sqrt{(-3)^{2} +(9)^{2}}= \sqrt{9+81} = \sqrt{90}= 9.49$
<span>
D = d1 + d2 + d3 = 10.63 + 13.93 + 9.49 = 34.05</span>

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