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Gnoma [55]
3 years ago
9

How many passwords can you have if there are 2 numbers and 3​ letters? (letters and numbers can​ repeat)

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
8 0

Answer:

D) 2,600.............

12345 [234]3 years ago
5 0

Answer:

d

Step-by-step explanation:

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Plz help<br> Will mark brainliest
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(0,-1)

Step-by-step explanation:

(0,-1) will work because when you plug them is it is equivalent to 4

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The product of 87(10000)
Lera25 [3.4K]

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870,000

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When multiplying the two you add as many 0's to 87 as there are in 10,000

8 0
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Math: <br> -x + 6 is greater than or equal to 10
Alla [95]

Answer:

It is actually less than 10.

Step-by-step explanation:

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3 years ago
I can’t seem to find the shaded area
mel-nik [20]

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8/21

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5 0
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Read 2 more answers
Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?
-BARSIC- [3]

The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>
  • In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

  1. U = {x | x is a real number}
  2. A = {x | x is an odd integer}
  3. R = {x | x = 3, 7, 11, 27}

So,

  • A = 1, 3, 5, 7, 9, 11... are the elements of set A.
  • R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
  • Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(C) no because each element in set A is not represented in set R

(D) no, because each element in set R is not represented in set A

8 0
1 year ago
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