It is not a function because there can't be two of the same number on the x-axis.
<u>Answer:</u>
When Anne pushes the wheelbarrow 25 meters the work done is 1120 joules
<u>Solution:</u>
We know ![\text { Work }(\mathrm{W})=\text { Force }(\mathrm{F})\times\text { Distance (D) }](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Work%20%7D%28%5Cmathrm%7BW%7D%29%3D%5Ctext%20%7B%20Force%20%7D%28%5Cmathrm%7BF%7D%29%5Ctimes%5Ctext%20%7B%20Distance%20%28D%29%20%7D)
Anne is pushing the wheelbarrow with a force of 70 N at an angle of
with the horizontal
So the force of Anne will be ![F=70 \cos 50^{\circ}=(70 \times 0.64)=44.8 \mathrm{N}](https://tex.z-dn.net/?f=F%3D70%20%5Ccos%2050%5E%7B%5Ccirc%7D%3D%2870%20%5Ctimes%200.64%29%3D44.8%20%5Cmathrm%7BN%7D)
She pushes the wheelbarrow 25 meter, So D = 25 meters
So, the ![work,F\times D=(44.8 \times 25)=1120 \text { Joules }](https://tex.z-dn.net/?f=work%2CF%5Ctimes%20D%3D%2844.8%20%5Ctimes%2025%29%3D1120%20%5Ctext%20%7B%20Joules%20%7D)
Anne has done total 1120 joules work.
You just take the difference between them and the answer is 1 3/5
Answer:
Point S represent the score 93.5 which is Drew's New Score.
Step-by-step explanation:
The score of Drew on a math test = 92
Point for each correction in the math test = 1/2 = 0.5
Now, the number of problems corrected = 3 x 0.5 = 1.5
So, Now, the new scale of Drew = Old Score + The Correction Score
= 92 + 1.5
= 93.5
or, Drew, new score = 93.5
Hence, point S represent the score 93.5 which is Drew's New Score.
Um well its quite common when going to the store and something is 50% off