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Aleksandr-060686 [28]
3 years ago
5

Use the figure below to answer these questions

Mathematics
2 answers:
slega [8]3 years ago
6 0

Answer:

thus is so easy

Step-by-step explanation:

too easy

Lina20 [59]3 years ago
4 0

Answer:

I expect this to be LI.

Step-by-step explanation:

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Rewrite in simplest terms: -9(5s – 6) + 9s
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-36s+54 i hope that was helpful

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Drupady [299]

So its X \leq 30

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The x equals the unknown amount or weight of her luggage.

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Select the quadratic equation that has roots x=8 and x=-5
stellarik [79]

Step-by-step explanation:

Since, x=8 and x=-5 are the roots.

Therefore, (x - 8) & (x - 5) will be factors.

Hence, required quadratic equation can be given as:

(x - 8)(x - 5) =0 \\  \\  \therefore  {x}^{2}  + ( - 8 - 5) x+ ( - 8) \times ( - 5) = 0 \\  \\ \therefore  {x}^{2}  + ( - 13) x+ 40= 0  \\  \\ \huge \red{ \boxed{ \therefore  {x}^{2}  - 13x+ 40= 0 }} \\ is \: the \: required \: quadratic \: equation.

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3 years ago
Find the square Root of <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B37%7D%20" id="TexFormula1" title=" \sqrt{37} " alt="
Zolol [24]

Answer:

\approx \frac{73}{12}\left(1 - \frac{1} {2\cdot73^2}\right)

Step-by-step explanation:

= \sqrt{\frac{73^2-1) 1}{12^2}} \\

= \sqrt{\frac{73^2}{12^2}\cdot\frac{73^2-1}{73^2}} \\

= \sqrt{\frac{73^2}{12^2}}\sqrt{\frac{73^2-1}{73^2}}\\

=\frac{73}{12}\sqrt{1 - \frac{1}{73^2}} \\

\approx \frac{73}{12}\left(1 - \frac{1} {2\cdot73^2}\right)

8 0
3 years ago
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