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3 years ago

13

75(1+0.2/12)^10*12 what is the answer

2 answers:

Alchen [17]3 years ago

8 0

Answer:

545.119

Step-by-step explanation:

75 * (1 + .2/12)^10 * 12

75 * (1.016667)^10*12

Now things get a little tricky. What does 10*12 mean? I'm taking it to mean 120

75 * (1.016667)^120

75 * 7.268

545.119

adoni [48]3 years ago

5 0

Answer:

1061.76487909 is the answer, and sorry i'm 4 days late with the answer.

Have a great day/night, and stay safe!

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X+13/2=4 what x equal

Harlamova29_29 [7]

Step-by-step explanation:

x+13÷2×2=4×2

x+13=8

x+13-13=8-13

x=8-13

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3 years ago

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If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by

PIT_PIT [208]

Answer:

The family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

$\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|}$ (1)

Where:

$\theta$ - Angle between vectors, in sexagesimal degrees.

$\|\vec a\|, \|\vec b \|$ - Norms of vectors $\vec {a}$ and $\vec{b}$

If $\theta$ is acute, then the cosine function is bounded between 0 a 1 and if we know that $\vec {a} = (p, 3, -7)$ and $\vec {b} = (p, -p, 4)$ , then the possible values for $p$ are:

Minimum ( $\cos \theta = 0$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0$

Maximum ( $\cos \theta = 1$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1$

With the help of a graphing tool we get the family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

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3 years ago

The Knicks and Nets have a total 30 players.

Blababa [14]

Answer:

Step-by-step explanation:

From the problem statement, we can set up the following two equations:

$K + N = 30$

$20K + 10N = 500$

where $K$ is the number of Knicks players, and $N$ is the number of Nets players.

We can substitute the first equation into the second and solve for $K$

$K + N = 30$

$N = 30 - K$

$20K + 10N = 500$

$20K + 10(30 - K) = 500$

$20K + 300 - 10K = 500$

$10K + 300 = 500$

$10K = 200$

$K = 20$

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yuradex [85]

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