Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
Total no. of times owner-occupied units had a water supply stoppage lasting 6 or more hours
547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000
x = no. of times owner-occupied units had a water supply stoppage.
<h3>What is the probability at x =0?</h3>
P(x=0) = 547000/14770000
P(x=0) = 0.0370
Similarly, we have at x=1
P(x=1) = 5012000/14770000
P(x=1) = 0.3393
P(x=2) = 6110000/14770000
P(x=2) = 0.4137
P(x=3) = 2544000/14770000
P(x=3) = 0.1722
P(x=4) = 557000/14770000
P(x=4) = 0.0378
x f(x)
0 0.0370
1 0.3393
2 0.4137
3 0.1722
4 0.0378
Total 1
Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
To learn more about the probability distribution visit:
brainly.com/question/24756209
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Well yeah it depends on the kids age and the parents age to
Angle R - Apex
Just took the quiz, the answer was Angle R.
Hope this helps people in the future
What are the options? But I think a good estimate is $700.
Let's set the measure of each angle equal to 540 degrees.
4x + 4x + 5x + 2 + 96 + 5x - 8 = 540
Combine like terms.
18x + 90 = 540
Subtract 90 from both sides.
18x = 450
Divide both sides by 18
x = 25
