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Yakvenalex [24]
3 years ago
12

There are 3 quarters, 5 dimes, and 2 nickels, in a jar. P(dime then dime without replacement)?​

Mathematics
1 answer:
Roman55 [17]3 years ago
3 0
Can yu give more explanation
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What is the sum of the next two terms in the sequence: -3, -1, 3, 9, 17
Korvikt [17]
Answer: 66 because you are adding 2 then 4 then 6 then 8 then 10 then 12 therefore 17+10= 27, and 27+12= 39 and 39+27 equals 66
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One​ ​day​ ​in​ ​Colorado​ ​it​ ​was​ ​-13.4​ ​degrees​ ​and​ ​then​ ​the​ ​temperature​ ​dropped​ ​another​ ​5.67 degrees​ ​ove
ratelena [41]

Answer:

-19.07

Step-by-step explanation:

6 0
2 years ago
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Select one of the factors of 5x2 + 7x + 2. a. (5x − 2) b. (x + 2) c. (5x + 1) d. None of the above
Elan Coil [88]
5x^{2}+7x+2=5x^{2}+5x+2x+2=5x(x+1)+2(x+1)= \\  \\ (5x+2)(x+1)

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<em />
<em>"Associate with people who are likely to improve you."</em>
7 0
3 years ago
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In the previous part, we obtained dy dx = 3t2 − 27 −2t . Next, find the points where the tangent to the curve is horizontal. (En
mina [271]

Answer:

(27.55, 7.22), (-11.3, 3.21).

Step-by-step explanation:

When is the tangent to the curve horizontal?

The tangent curve is horizontal when the derivative is zero.

The derivative is:

\frac{dy}{dx} = 3t^{2} - 2t - 27

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

3t^{2} - 2t - 27 = 0

So

a = 3, b = -2, c = -27

Then

\bigtriangleup = b^{2} - 4ac = (-2)^{2} - 4*3*(-27) = 328

So

t_{1} = \frac{-(-2) + \sqrt{328}}{2*3} = 3.35

t_{2} = \frac{-(-2) - \sqrt{328}}{2*3} = -2.685

Enter your answers as a comma-separated list of ordered pairs.

We found values of t, now we have to replace in the equations for x and y.

t = 3.35

x = t^{3} - 3t = (3.35)^{3} - 3*3.35 = 27.55

y = t^{2} - 4 = (3.35)^2 - 4 = 7.22

The first point is (27.55, 7.22)

t = -2.685

x = t^{3} - 3t = (-2.685)^3 - 3*(-2.685) = -11.3

y = t^{2} - 4 = (-2.685)^2 - 4 = 3.21

The second point is (-11.3, 3.21).

8 0
3 years ago
casandra is traning for a 10 mile race. on the first day of training she runs 4 miles, each day after that she adds on 0.5 mile
Anna11 [10]
On the ninth day. Y=0.5x + 4
3 0
3 years ago
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