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Yakvenalex [24]
3 years ago
12

There are 3 quarters, 5 dimes, and 2 nickels, in a jar. P(dime then dime without replacement)?​

Mathematics
1 answer:
Roman55 [17]3 years ago
3 0
Can yu give more explanation
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How could you use a number line to show that -4 + 3 and -3 + (-4)
Nonamiya [84]
Move negative 4 to the right till you get to positive 3. Then Move negative 3 to the left 4 times
8 0
3 years ago
What is an expression for "Four subtracted from the quotient of X and 3
LUCKY_DIMON [66]
" the quotient " means divide

(x/3) - 4 <== ur expression
4 0
3 years ago
Read 2 more answers
Rewrite the equation below so that it does not have fractions.
Andru [333]

Answer:

x= - 50/9

Step-by-step explanation:

multipy both equations by 12

9x+60=10

then move the constant to the right hand side and change it's sign

9x= 10 - 60

calculate difference

9x = -50

divide both sides by 9

x= - 50/9

6 0
1 year ago
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Which transformation will map figure Honto figure H? (1 point)
podryga [215]

Answer:

2) Vertical translation of 10 units

Step-by-step explanation:

Given

H and H'

Required

Which maps H to H'

First, we pick the coordinate of any point on H

H(x,y) = (4,2)

First, we pick a corresponding coordinate on H'

H'(x,y) = (4,-8)

The above coordinates show that H and H' are not a reflection of one another because neither of the x or y coordinates negate one another.

By looking at the coordinates of H and H, we have:

H: x = 2 and H':x = 2 ---  The same x coordinates

H: y = 2 and H': y = -8 --- Different y coordinates

The difference between the y coordinates is:

Difference  = H(x) - H'(x)

Difference  = H(2) - H'(2)

Difference  = 2 - (-8)

Difference  = 2 +8

Difference  = 10

Hence,

<em>2) Vertical translation of 10 units </em> is correct.

3 0
3 years ago
In triangle ABC, if an exterior angle drawn at vertex C
Lorico [155]

Answer:

Part 1) Option D. must be an acute angle

Part 2) m∠A=70°

Step-by-step explanation:

Part 1) In triangle ABC, if an exterior angle drawn at vertex C  measures 45, then angle B...

we know that

An exterior angle of a triangle is equal to the sum of the opposite interior angles

so

The measure of an exterior angle at C is equal to the sum of the interior angles at A and B

we have that

45°=m∠A+m∠B

therefore

m∠B < 90°

Angle B must be an acute angle

Part 2)

we know that

An exterior angle of a triangle is equal to the sum of the opposite interior angles

so

The measure of an exterior angle at B is equal to the sum of the interior angles at A and C

m∠A+m∠C=2m∠C+5

m∠C=m∠A-5 ----> equation A

m∠C=65° ----> equation B

substitute equation B in equation A

65°=m∠A-5

m∠A=(65+5)°=70°

3 0
3 years ago
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