Pls helpppp helpppppp

Given: 5 > x + 7. Choose the graph of the solution set.

mariarad [96]

Option B is the correct option.

please see the attached picture for full solution..

Hope it helps...

Good luck on your assignment....

3 0

3 years ago

The current of a river is 4 miles per hour. A boat travels to a point 30 miles upstream and back in 4 hours. What is the speed o

Maurinko [17]

16 mph is the answer I found after doing the work

7 0

3 years ago

What is the slope of the line

STALIN [3.7K]

The answer you chose in the photo is correct !!

5 0

3 years ago

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 430 gram setting. It is

Leto [7]

Answer:

$t=\frac{435-430}{\frac{29}{\sqrt{23}}}=0.827$

The degrees of freedom are given by:

$df=n-1=23-1=22$

And the p value taking in count that we have a bilateral test we got:

$p_v =2*P(t_{(22)}>0.827)=0.417$

Since the p value is higher than the significance level of 0.05 we have enough evidence to conclude that the true mean is not significantly different from 430 the required value

Step-by-step explanation:

Information given

$\bar X=435$ represent the mean for the weight

$s=\sqrt{841}=29$ represent the sample standard deviation

$n=23$ sample size

$\mu_o =430$ represent the value that we want to verify

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We are trying to proof if the filling machine works correctly at the 430 gram setting, so then the system of hypothesis for this case are:

Null hypothesis: $\mu = 430$

Alternative hypothesis: $\mu \neq 430$

In order to cehck the hypothesis the statistic for a one sample mean test is given by

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we have this:

$t=\frac{435-430}{\frac{29}{\sqrt{23}}}=0.827$

The degrees of freedom are given by:

$df=n-1=23-1=22$

And the p value taking in count that we have a bilateral test we got:

$p_v =2*P(t_{(22)}>0.827)=0.417$

Since the p value is higher than the significance level of 0.05 we have enough evidence to conclude that the true mean is not significantly different from 430 the required value

8 0

3 years ago

The vertices of a rectangle are Q (2, -3), R (2,4), S (5,4), and T (5, -3).

disa [49]

4) $A_{QRST} = A_{Q'R'S'T'} = 9$ .

5) The areas of the rectangles QRST and Q'R'S'T' are the same since the translation of the geometric loci conserved the Euclidean distance.

6) x = 1, w = 3, y = - 1/4, z = 1/3

<h3>How to analyze and apply rigid transformations</h3>

Rigid transformations are transformations applied on geometric loci such that Euclidean distance is conserved. In this question we have applications of translations, a kind of rigid transformation.

Exercise 4

In this part we must determine the areas of rectangles QRST and Q'R'S'T':

Rectangle QRST

A = RS · QT

A = 3 · 3

A = 9

Rectangle Q'R'S'T'

Q'(x, y) = (2, - 3) + (- 3, - 3)

Q'(x, y) = (- 1, - 6)

R'(x, y) = (2, 4) + (- 3, - 3)

R'(x, y) = (- 1, 1)

S'(x, y) = (5, 4) + (- 3, - 3)

S'(x, y) = (2, 1)

T'(x, y) = (5, - 3) + (- 3, - 3)

T'(x, y) = (2, - 6)

A = R'S' · Q'T'

A = 3 · 3

A = 9

The rectangles QRST and Q'R'S'T' have both an area of 9 square units.

Exercise 5

The areas of the rectangles QRST and Q'R'S'T' are the same since the translation of the geometric loci conserved the Euclidean distance.

Exercise 6

In this case, we must solve the following equations:

PQ = A'(x, y) - A(x, y)

(4, 1) = (2 · x + 1, 4) - (- 1, w)

(4, 1) = (2 · x + 2, 4 - w)

(4, 1) = (2 · x, - w) + (2, 4)

(2, - 3) = (2 · x, - w)

(x, w) = (1, 3)

PQ = B'(x, y) - B(x, y)

(4, 1) = (3, 3 · z) - (8 · y - 1, 1)

(4, 1) = (2 - 8 · y, 3 · z)

(4, 1) = (- 8 · y, 3 · z) + (2, 0)

(2, 1) = (- 8 · y, 3 · z)

(y, z) = (- 1/4, 1/3)

To learn more on translations: brainly.com/question/17485121

#SPJ1

3 0

2 years ago