Answer:
both fireworks will explode 4.5 seconds after Firework B launches
Step-by-step explanation:
Given;
speed of firework A,
= 360 ft/s
speed of firework B,
= 340 ft/s
If the two fireworks explodes at the same height, then the height attained by the two fireworks are equal.
let the distance traveled by each firework before explosion = d
Distance = speed x time
Distance A = Distance B
speed A x time = speed B x time
let the time both fireworks explodes after Firework B launches = t
(
) t = (
) t
360t = 340t
if firework B is launched 0.25 s before Firework A, for the time of the two fireworks to be equal since we are considering time (t) after 0.25 seconds, we will have;
360(t-0.25) = 340t
360t - 90 = 340t
360 t - 340 t = 90
20 t = 90
t = 90/20
t = 4.5 seconds
Therefore, both fireworks will explode 4.5 seconds after Firework B launches
Answer:
The car will travel 29 1/3 miles in 44 minutes, 40 miles in an hour.
Step-by-step explanation:
First, find how far the car can travel in one minute.
(1 1/2)/(2 1/4)=(2/3)
Then multiply the amount of time in minutes.
(2/3)*44= 29 1/3
(2/3)*60=40
Answer:
Step-by-step explanation:
620.50 * 12 = 7,446
597.20 * 12 = 7,116.4
7446 - 7116.4 = 329.6
Answer:
14
Step-by-step explanation:
Answer: Sup. it's 16
Step-by-step explanation: Hope dis helps
if x = 2 and our equation is 10 +3(12 ÷ 3x), then u use substitution
So, the equation would become 10 + 3(12 ÷ 3(2)), which is 10 + 3(12 ÷ 6)
12÷6= 2, so the equation becomes 10 + 3(2).
3(2) = 6, so the equation would be 10 + 6 = 16